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2 years ago

(X + 4) + ( x + 4 ) + x + x

Mathematics

1 answer:

weeeeeb [17]2 years ago

4 0

Answer: 4x + 8
Simplify the x’s and then the normal value, it’s basically just addition.

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1. Which lines or segments are parallel? Justify your answer.

Rainbow [258]

Answer:

Segment CA || Segment HR (by Converse of the Corresponding Angles Postulate)

Step-by-step explanation:

Postulate Segment CA || Segment HR by Converse of the Corresponding Angles

8 0

2 years ago

4x + 1 = 2x – 5 can someone help me. Whoever gets it right gets it right gets brainliest

castortr0y [4]

Answer:

x=-3

Step-by-step explanation:

subtract "2x" to "4x + 1" and that'll leave -5 by itself and leave 2x+1 on the left and -5 on the right then subtract -1 to -5 and it'll add up to -6 then after that you'd divide 2x to -6 and get -3 and it'll leave 'x' by itself so therefore X = -3

3 0

3 years ago

Read 2 more answers

A triangle has side lengths of 7 in., 9 in., and 11 in. Determine whether this is a right triangle and why.

Harlamova29_29 [7]

Answer:

Not a right triangle. See below for my reasoning.

Step-by-step explanation:

If this is a right triangle, then the sum of the squares of the two shorter sides will equal the square of the longest side: 7^2 + 9^2 = 11^2 => 49 + 81 = 121 But this is false.

8 0

2 years ago

The population of cats in a rural neighborhood has declined in the last year by roughly 30%. Residents hypothesize that this is

zvonat [6]

Answer:

Orinal number of cats= 171

Step-by-step explanation:

Giving the following information:

Decrease in population= 30%

Current population= 120

<u>To calculate the original number of cats, we need to use the following formula:</u>

Orinal number of cats= current population / (1 - decrease)

Orinal number of cats= 120 / (1 - 0.3)

Orinal number of cats= 171

8 0

2 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider