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2 years ago

6 to the 5 power times 6 to the negative 2 power= ?

Mathematics

1 answer:

guapka [62]2 years ago

8 0

The answer the the question Is 5

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A set of composite number less than 12.Express it in listing and set-builder methods

Ivanshal [37]

composite numbers less than 12={1,3,4,6,8,9,10}

7 0

3 years ago

Reena bought a mobile phone for 16,240 that included a GST of 12%. Find the price of the mobile phone before the GST was added.

NNADVOKAT [17]

Answer: 14500

Step-by-step explanation:

Let the price of the mobile phone before the GST was added be represented by x.

Therefore,

x + (12% × x) = 16240

x + 0.12x = 16240

1.12x = 16240

x = 16240/1.12

x = 14500

The price of the mobile phone before the GST was added was 14500

4 0

3 years ago

If 38 = 11 + 3x, what is the value of x ?

Serhud [2]

Answer:

38-11=3x

27=3x

27/3=x

x=9

3 0

3 years ago

Read 2 more answers

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

2 years ago

omar is saving to buy a game hes saved 30 dollars which is six-fifths of total game cost. how much does it cost?

Rzqust [24]

The game costs 25 dollars. If 6/5 = 30 then 5/5 would be 25

3 0

3 years ago