Question

Each of the equal sides of an isosceles triangle exceeds 3 times the base by 2 inches. If the perimeter is 60 inches, find the length of each side of the triangle..help pleasee.

Answer 1

Sides are x,x,b


x is identical side

x is bigger than 3 times b by 2
x=3b+2

p=x+x+b
60=2x+b

x=3b+2
60=2(3b+2)+b
60=6b+4+b
60=7b+4
minus 4 both sides
56=7b
divide both sides by 7
8=b

sub back
x=3b+2
x=3(8)+2
x=24+2
x=26


legnths are
26in, 26in, 8in