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murzikaleks [220]
3 years ago
9

What is 8+24÷(2×6_4 what is the strategy I used and what's the answer

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0
There is a problem with your question. it doesn't make sense ???
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Mark all of the statements that are true.
11Alexandr11 [23.1K]

Answer:

a

Step-by-step explanation:

6 0
3 years ago
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
Explain WHAT WOULD HAPPEN TO motion IF friction DID NDT EXIST.
MA_775_DIABLO [31]

Answer:

If friction did not exist, it would be hard for us to slow down in running, or putting breaks on a car, and more!

If friction did not exist, your car will slide down the road even if you try your best to put the brakes on a car. Friction is a very important force to slow down things that are moving very fast

Step-by-step explanation:

Hoped this helped.

GeniusUser

5 0
3 years ago
Neeeeeed the help please
lions [1.4K]
The correct answer is -5/7. Hope this helps.
8 0
3 years ago
Unit 8: Right Triangles &amp; Trigonometry<br> Homework 2: Special Right Triangles
Kamila [148]

Answer:

17. z=39/sin45=78/\sqrt{2}

    y=39/tan60=39/\sqrt{3}

    x=y/sin60=78/\sqrt{3}

19. x=6\sqrt{3}/tan60=6

    y=2x=12

    z=\sqrt{2}y=12\sqrt{2}

Step-by-step explanation:

17.

because:sin45=39/z    

so:     z=39/sin45=78/\sqrt{2}

then: tan60=39/y

so:    y=39/tan60=39/\sqrt{3}

last:  sin60=y/x

so:    x=y/sin60=78/\sqrt{3}

19.

because: tan60=6\sqrt{3}/x

so:            x=6\sqrt{3}/tan60=6

then:        sin30=x/y

so:            y=x*sin30=2x=12

last:          sin45=y/z

so:            z=sin45*y=\sqrt{2}y=12\sqrt{2}

   

4 0
2 years ago
Read 2 more answers
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