Answer:
Check this explaination below
Step-by-step explanation:
Check the attached picture
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
C=2pr, r=c/(2p)
a=pr^2, using r found above we get:
a=p(c^2/(4p^2))
a=(c^2)/(4p), since c=106.76 and we approximate pi as 3.14
a=(106.76^2)/(4*3.14)
a=11612.2176/12.56 cm^2
a≈924.54 cm^2 (to nearest one-hundredth of a square cm)
The unit rate is $8/hr and the equation for y would be y=2x. The slope would be 8
