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ExtremeBDS [4]
2 years ago
15

Explain why the duster accelerates different rates when different surfaces are in contact with the track

Physics
2 answers:
vichka [17]2 years ago
8 0

Answer:

Because on different surfaces there's more/less friction. Smooth surfaces will allow the duster to accelerate while rough surfaces will decrease the acceleration.

grandymaker [24]2 years ago
4 0

Answer:

Because of the difference in the magnitude of friction.

Explanation:

Friction is defined as the force which is produced between the two surfaces when these two surfaces are in contact with each other.

When we observing the different surfaces there will be different value of friction it is less or high with respect to different surfaces.

Smooth surfaces which posses less friction allow duster to accelerate while on the other hand rough surface will decrease the acceleration of the duster due to high friction.

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Kate walks up to an automated teller machine and pushes a button. The pressure exerted by her finger is transformed into electri
lozanna [386]
The answer is Transduction .
8 0
3 years ago
Find the current in the 12 ohm resistor.
disa [49]

Answer:

1.5 A

Explanation:

V =I.R

18 = I × 12

I = 18/12

= 3/2 = 1.5 A

3 0
3 years ago
A particle, whose acceleration is constant, is moving in the negative x direction at a speed of 4.91 m/s, and 12.9 s later the p
Zinaida [17]

Answer:

The particle’s velocity is -16.9 m/s.

Explanation:

Given that,

Initial velocity of particle in negative x direction= 4.91 m/s

Time = 12.9 s

Final velocity of particle in positive x direction= 7.12 m/s

Before 12.4 sec,

Velocity of particle in negative x direction= 5.32 m/s

We need to calculate the acceleration

Using equation of motion

v = u+at

a=\dfrac{v-u}{t}

Where, v = final velocity

u = initial velocity

t = time

Put the value into the equation

a=\dfrac{7.12-(-4.91)}{12.9}

a=0.933\ m/s^2

We need to calculate the initial speed of the particle

Using equation of motion again

v=u+at

u=v-at

Put the value into the formula

u=-5.321-0.933\times12.4

u=-16.9\ m/s

Hence, The particle’s velocity is -16.9 m/s.

4 0
3 years ago
Later, while taking your groceries back to the car, you accidentally let go of your cart. It rolls straight down a grassy slope
VladimirAG [237]

Car is moving on the glassy slope with constant speed

Now we know that

a = \frac{dv}{dt}

so acceleration is rate of change in velocity

as we know that velocity is constant here so acceleration is zero

so here

a = 0

now as we know by Newton's II law

F = ma

since a = 0

F = 0

so net force will be ZERO on it during this motion

6 0
3 years ago
In classical physics, consider a 2 kg block hanging on a spring with a spring constant of 50 N/m. Ignore air resistance. The blo
RUDIKE [14]

Answer:

v = 0

Explanation:

This problem can be solved by taking into account:

- The equation for the calculation of the period in a spring-masss system

T = \sqrt{\frac{m}{k} }     ( 1 )

- The equation for the velocity of a simple harmonic motion

x = \frac{2\pi }{T}Asin(\frac{2\pi }{T}t)   ( 2 )

where m is the mass of the block, k is the spring constant, A is the amplitude (in this case A = 14 cm) and v is the velocity of the block

Hence

T = \sqrt{\frac{2 kg}{50 N/m}} = 0.2 s

and by reeplacing it in ( 2 ):

v = \frac{2\pi }{0.2s}(14cm)sin(\frac{2\pi }{0.2s}(0.9s)) = 140\pi  sin(9\pi ) = 0

In this case for 0.9 s the velocity is zero, that is, the block is in a position with the max displacement from the equilibrium.

5 0
3 years ago
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