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postnew [5]
3 years ago
5

What is the acceleration of a boy on a skateboard if the net force on the boy is 15 N? The total mass of the boy and the skatebo

ard is 58 kg.
Physics
2 answers:
Stels [109]3 years ago
7 0
                                 Force = (mass) x (acceleration)

If the full 15N is pointing parallel to the ground,
then

                                   15 N  =  (58 kg) x (acceleration).

Divide each side
by  58 kg:                   Acceleration = 15 N / 58 kg

                                                         = (15 kg-m/s²) / (58 kg)

                                                         = (15/58) (kg-m/kg-s²)

                                                         =  0.26 m/s² .
masya89 [10]3 years ago
6 0
Force = mass*acceleration
15 = 58 * x
x = 15 / 58
x = 0.26m/s²
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Answer:

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4 years ago
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Answer:

0 N

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3 years ago
Projectiles that strike objects are good examples of inelastic collisions. A 0.1 kg nail driven by a gas powered nail driver col
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In an inelastic collision, only momentum is conserved, while energy is not conserved.

1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:
p_f=(m+M)v_f=4.8 kg m/s
where
m=0.1 kg is the mass of the nail
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2) The velocity of the nail before the collision can be found by using the conservation of momentum. In fact, the total momentum before the collision is given only by the nail (since the block is at rest), and it must be equal to the total momentum after the collision:
p_i = mv_i = p_f
Rearranging the formula, we can find v_i, the velocity of the nail before the collision:
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6 0
3 years ago
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In case of perfectly inelastic collision v'1 and v'2 are same.

We are given information:
m₁=0.5kg
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v₁=3m/s
v₂=2m/s
v'₁=v'₂=x

0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
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4 0
3 years ago
Help me plsssss<br> help me plsssss
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Answer:


It is d. 0.80
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