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vesna_86 [32]
3 years ago
8

When light strikes an opaque material, which of the following accurately describes what happens to the light rays? Some of the l

ight passes through it but that light is quickly scattered; some of the light is absorbed as heat and some is reflected off the surface Most of the light passes through it, but some is also reflected and refracted None of the light passes through it; some of the light is absorbed as heat but most is reflected off the surface Half of the light rays pass through heating the substance and the other half are reflected off the surface casting a shadow
Physics
2 answers:
ExtremeBDS [4]3 years ago
8 0
<span>None of the light passes through it; some of the light is absorbed as heat but most is reflected off the surface.  This is how you see </span>objects.  reflected light from them hits your eye.  (Opaque means not transparent)
statuscvo [17]3 years ago
8 0

Answer:

None of the light passes through it some of the light is absorbed as heat but most is reflected off the surface

Explanation:

The materials are of three types i.e. transparent, translucent and opaque materials. Opaque materials are the materials that do not allow the light rays to pass through it. Some of the examples of opaque materials are wood, metals, dark colored plastics, bricks etc.

Usually light some many phenomenons like scattering, absorption, reflection etc.

Hence, the correct statement about opaque material is " None of the light passes through it, some of the light is absorbed as heat but most is reflected off the surface".

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Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 23.5 m above water wit
Elodia [21]

As stated in the statement, we will apply energy conservation to solve this problem.

From this concept we know that the kinetic energy gained is equivalent to the potential energy lost and vice versa. Mathematically said equilibrium can be expressed as

\Delta KE = \Delta PE

\frac{1}{2}mv_f^2-\frac{1}{2} mv_0^2 = mgh_2-mgh_1

Where,

m = mass

v_{f,i} = initial and final velocity

g = Gravity

h = height

As the mass is tHe same and the final height is zero we have that the expression is now:

\frac{1}{2}v_f^2-\frac{1}{2} v_0^2 = gh_2

\frac{1}{2} (v_f^2-v_0^2) = gh_2

(v_f^2-v_0^2) = 2gh_2

v_f = \sqrt{2gh_2+v_0^2}

v_f = \sqrt{2(9.8)(23.5)+13.6^2}

v_f = 25.4m/s

7 0
3 years ago
a 100 g cart initially moving at 0.5 m/s collides elastically from a stationary 180 g cart. a) using the equation in the theory,
cupoosta [38]

A 100 g cart is moving at 0.5 m/s that collides elastically from a stationary 180 g cart. Final velocity is calculated to be 0.25m/s.

Collision in which there is no net loss in kinetic energy in the system as a result of the collision is known as elastic collision . Momentum and kinetic energy both are conserved quantities in elastic collisions.

Collision in which part of the kinetic energy is changed to some other form of energy is inelastic collision.

For an elastic collision, we use the formula,

m₁V₁i+ m₂V₂i = m₁V1f + m₂V₂f

For a perfectly elastic collision, the final velocity of the 100g cart will each be 1/2 the velocity of the initial velocity of the moving cart.

Final velocity = 0.5/2

=0.25 m/s.

To know more about elastic collision, refer

brainly.com/question/7694106

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7 0
1 year ago
Many organ system serve to help maintain a healthy body. The excretory system is an organ system which is composed of all sweat
Cerrena [4.2K]

Answer: D

Explanation:

Cause removing excess waste from the body helps to maintain a steady health

3 0
3 years ago
A jetliner is traveling east from Salt Lake City to Washington DC, a distance of 1,850 miles. The jetliner travels at an average
maks197457 [2]
The jetliner is traveling against the wind. The net speed of the jetliner is
590 mph - 36 mph = 554 mph
The time it takes for the jetliner to arrive at the destination is
1850 miles / 554 mph = 3.34 hours
3 0
3 years ago
at the center of the neutral metal block, what is the direction of the electric field contributed by the charge in and on the me
elena-14-01-66 [18.8K]

The direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

<h3>How to determine electric field direction in a metal block?</h3>

The charge always remain on outer surface of metal and inside the metal block, the net electric field is zero. But due to dipole there is an electric field at the center of metal block i.e. at point R along direction line 1.

Now, to make make the net electric field zero at center, the electric field by the charge in and on the metal block must be equal in magnitude to that of electric field due to dipole at point R and in opposite direction to that of the net electric field at at R due to dipole.

The electric field by the charge in and on the metal block will be making 180° angle to the  electric field due to dipole at point R.

Hence the direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

To know more about electric field, click on brainly.com/question/11509296

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4 0
1 year ago
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