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vesna_86 [32]
3 years ago
8

When light strikes an opaque material, which of the following accurately describes what happens to the light rays? Some of the l

ight passes through it but that light is quickly scattered; some of the light is absorbed as heat and some is reflected off the surface Most of the light passes through it, but some is also reflected and refracted None of the light passes through it; some of the light is absorbed as heat but most is reflected off the surface Half of the light rays pass through heating the substance and the other half are reflected off the surface casting a shadow
Physics
2 answers:
ExtremeBDS [4]3 years ago
8 0
<span>None of the light passes through it; some of the light is absorbed as heat but most is reflected off the surface.  This is how you see </span>objects.  reflected light from them hits your eye.  (Opaque means not transparent)
statuscvo [17]3 years ago
8 0

Answer:

None of the light passes through it some of the light is absorbed as heat but most is reflected off the surface

Explanation:

The materials are of three types i.e. transparent, translucent and opaque materials. Opaque materials are the materials that do not allow the light rays to pass through it. Some of the examples of opaque materials are wood, metals, dark colored plastics, bricks etc.

Usually light some many phenomenons like scattering, absorption, reflection etc.

Hence, the correct statement about opaque material is " None of the light passes through it, some of the light is absorbed as heat but most is reflected off the surface".

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if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?
Strike441 [17]

Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

4 0
3 years ago
Read 2 more answers
In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin
alexandr402 [8]

Answer:

a) v=0.999124c

b) E=7.566*10^{22}

c) E_a=760 times\ larger

Explanation:

From the question we are told that

Distance to Betelgeuse d_b=430ly

Mass of Rocket M_r=20000

Total Time in years traveled T_d=36years

Total energy used by the United States in the year 2000 E_{2000}=1.0*10^20

Generally the equation of speed of rocket v mathematically given by

v=\frac{2d}{\triangle t}

v=860ly/ \triangle t

where

\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\sqrt{(860)^2+(36)^2}

\triangle t=860.7532

Therefore

v=\frac{860ly}{ 860.7532}

v=0.999124c

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2

E=7.566*10^{22}

c)Generally the equation of the energy E_a required to accelerate the rocket mathematically given by

E_a=\frac{E}{E_{2000}}

E_a=\frac{7.566*10^{22}}{1.0*10^{20}}

E_a=760 times\ larger

8 0
3 years ago
In which of these situations is convection most likely the main form of heat transfer? A.Warm air from a heater on the first flo
Sergeeva-Olga [200]
All points ate true

But option A is perfect
6 0
3 years ago
Read 2 more answers
Continuous sinusoidal perturbation Assume that the string is at rest and perfectly horizontal again, and we will restart the clo
Elena-2011 [213]

a) 3.14 \cdot 10^{-4} s

b) See plot attached

c) 10.0 m

d) 0.500 cm

Explanation:

a)

The position of the tip of the lever at time t is described by the equation:

y(t)=(0.500 cm) sin[(2.00\cdot 10^4 s^{-1})t] (1)

The generic equation that describes a wave is

y(t)=A sin (\frac{2\pi}{T} t) (2)

where

A is the amplitude of the wave

T is the period of the wave

t is the time

By comparing (1) and (2), we see that for the wave in this problem we have

\frac{2\pi}{T}=2.00\cdot 10^4 s^{-1}

Therefore, the period is

T=\frac{2\pi}{2.00\cdot 10^4}=3.14 \cdot 10^{-4} s

b)

The sketch of the profile of the wave until t = 4T is shown in attachment.

A wave is described by a sinusoidal function: in this problem, the wave is described by a sine, therefore at t = 0 the displacement is zero, y = 0.

The wave than periodically repeats itself every period. In this sketch, we draw the wave over 4 periods, so until t = 4T.

The maximum displacement of the wave is given by the value of y when sin(...)=1, and from eq(1), we see that this is equal to

y = 0.500 cm

So, this is the maximum displacement represented in the sketch.

c)

When standing waves are produced in a string, the ends of the string act as they are nodes (points with zero displacement): therefore, the wavelength of a wave in a string is equal to twice the length of the string itself:

\lambda=2L

where

\lambda is the wavelength of the wave

L is the length of the string

In this problem,

L = 5.00 m is the length of the string

Therefore, the wavelength is

\lambda =2(5.00)=10.0 m

d)

The amplitude of a wave is the magnitude of the maximum displacement of the wave, measured relative to the equilibrium position.

In this problem, we can easily infer the amplitude of this wave by looking at eq.(1).

y(t)=(0.500 cm) sin[(2.00\cdot 10^4 s^{-1})t]

And by comparing it with the general equation of a wave:

y(t)=A sin (\frac{2\pi}{T} t)

In fact, the maximum displacement occurs when the sine part is equal to 1, so when

sin(\frac{2\pi}{T}t)=1

which means that

y(t)=A

And therefore in this case,

y=0.500 cm

So, this is the displacement.

6 0
3 years ago
What is its speed after 3. 83 as if it accelerates uniformly at −3. 04 m/s 2 ? answer in units of m/s.
weeeeeb [17]

The velocity equation is v_{final} =v_{initial} +at\\

Known facts:

  • t = 3.83s
  • a= -3.04
  • intial velocity = 0

Plug into equation known quantities:

   v_{final} = (-3.04) * 3.83 = -11.6432m/s

Thus the final velocity is -11.6432m/s

Hope that helps!

6 0
3 years ago
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