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8090 [49]
2 years ago
6

Help me with this please​

Physics
2 answers:
mina [271]2 years ago
6 0
Do not wash do not dry
Elanso [62]2 years ago
4 0

care labels

2. do not dry wash

do not iron

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3 years ago
Write two units for electric field intensity and show thier equivalence?​
nataly862011 [7]

Answer:

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3 years ago
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Sophie throws a tennis ball down from a height of 1.5 m at an angle of 450 with respect to vertical. She drops another tennis ba
Katena32 [7]

Given that,

Height =1.5 m

Angle = 45°

We need to find the greater speed of the ball

Using conservation of energy

P.E_{i}+K.E_{f}=P.E_{f}+K.E_{f}

mgh+\dfrac{1}{2}mv_{i}^2=mgh+\dfrac{1}{2}mv_{f}^2

Here, initial velocity and final potential energy is zero.

mgh=\dfrac{1}{2}mv_{f}^2

Put the value into the formula

9.8\times1.5=\dfrac{1}{2}v_{f}^2

v_{f}^2=2\times9.8\times1.5

v_{f}=\sqrt{2\times9.8\times1.5}

v_{f}=5.42\ m/s

Hence, the greater speed of the ball is 5.42 m/s.

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2 years ago
PLEASE HELP/// <br> how many Croatian Music Awards has 2cello won
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2 years ago
A sphere of plastic of radius = .100 m is completely immersed in water. The density of the plastic is 600 kg/m3. Since the plast
tekilochka [14]

To solve this problem we need to use the proportional relationships between density, mass and volume, together with Newton's second law.

The force can be described as

F = ma \rightarrow mg

Where,

m = Mass

g = Gravitational acceleration

At the same time the Density can be defined as

\rho = \frac{m}{V} \rightarrow m = \rho V

Where,

m = mass

V = Volume

Replacing the value of the mass at the equation of Force we have,

F = \rho V g

Since the difference between the two forces gives us the total Force then we have to

F_T = F_w - F_p

Where

F_w = Force of the water

F_p= Force of plastic

Therefore with the values for this force we have,

F_T = \rho_w Vg - \rho_p Vg

F_T = Vg(\rho_w - \rho_p)

F_T = (\frac{4}{3} \pi r^3) g(\rho_w - \rho_p)

F_T = (\frac{4}{3} \pi (0.1)^3) (9.8)(1000 - 600)

F_T = 16.412 N

Therefore the tension in the thread is 16.412N

3 0
3 years ago
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