Use stoichiometric ratio to determine which is in excess and which is limiting
2.0 MOL is the correct answer I believe
109/8.56=12.7
50+12.7
V=62.7
Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer
Answer:
1) n-Hexane. 2) 2-Methyl pentane(IUPAC name) or Isohexane(common name). 3) 2,2-Dimethylbutane(IUPAC name) or Neohexane(common name). 4) 3-Methylpentane
Explanation:
The specific heat capacity of unknown substance is 1.333 g/j/°c
<u><em> calculation</em></u>
Specific heat capacity is calculated using Q= MCΔT formula
where;
Q(heat)= 800 j
M(mass) = 30 g
C(specific heat capacity) =?
ΔT( change in temperature) = 40°c - 20°c = 20°c
make C the subject of the formula by diving both side of the formula by MΔT
C is therefore = Q/MΔT
800j / 30 g x 20°c = 1.333 j/g/°c
