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ZanzabumX [31]
3 years ago
10

I think it's be but I'm not sure

Chemistry
1 answer:
Morgarella [4.7K]3 years ago
6 0
The correct answer is b
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The mass of sodium chloride at the two parts are mathematically given as

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  • mass of Nacl(m)=39.15g

<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Where the chemical equation is

F2 + 2NaCl → Cl2 + 2NaF

Therefore

1.50x15=m/M *(1.50*0.0821)

1-50 x 15=m/58.5 *(1.50*0.0821)

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Part 2

PV=m'/MRT

1*15=m'/58.5*0.0821*273

m'=39.15g

mass of Nacl(m)=m'=39.15g

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3 years ago
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