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valina [46]
4 years ago
10

Can someone help me to answer these Chemistry questions?

Chemistry
1 answer:
Andreyy894 years ago
3 0
Which ones in specific
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If the mass of an object is 60.0 grams and the density of the object is 15.0 g/mL, what is the volume of the object? The formula
laila [671]

Answer:

168.56 mL

Explanation:

density = mass/volume, use basic algebra skills to replace the volume and solve

7 0
3 years ago
What happens to excess heat produced in the muscle during contraction and relaxation
Afina-wow [57]

Answer:

Calcium is then pumped back into the sarcoplasmic reticulum breaking the link between actin and myosin.

Explanation:

Actin and myosin return to their unbound state causing the muscle to relax. Alternatively relaxation (failure) will also occur when ATP is no longer available.

3 0
2 years ago
When aqueous solutions of lead(II) nitrate and potassium iodide are mixed, what is the formula for the insoluble solid (precipit
andrew-mc [135]

Answer:

The formula for the precipitate is PbI₂

Explanation:

The chemical reaction is:

Pb(NO₃)₂ (aq)  +  2KI (aq)  →  2KNO₃ (aq) + PbI₂ (s)↓

All the iodides, with these cations (Ag⁺, Pb²⁺, Cu⁺, Hg²⁺, Bi⁺³ and Sn⁺⁴) produce insolubles solid.

7 0
3 years ago
Which of the following is NOT a heterogenous mixture:
ANTONII [103]

Answer:Vinegar

Explanation:

4 0
3 years ago
Promethium-147 is sometimes used in luminescent paint. It has a half-life of 956.3 days. If 250 grams (g) of promethium-147 is u
Fantom [35]

Answer:

% = 76.75%

Explanation:

To solve this problem, we just need to use the expressions of half life and it's relation with the concentration or mass of a compound. That expression is the following:

A = A₀ e^(-kt)   (1)

Where:

A and A₀: concentrations or mass of the compounds, (final and initial)

k: constant decay of the compound

t: given time

Now to get the value of k, we should use the following expression:

k = ln2 / t₁/₂   (2)

You should note that this expression is valid when the reaction is of order 1 or first order. In this kind of exercises, we can assume it's a first order because we are not using the isotope for a reaction.

Now, let's calculate k:

k = ln2 / 956.3

k = 7.25x10⁻⁴ d⁻¹

With this value, we just replace it in (1) to get the final mass of the isotope. The given time is 1 year or 365 days so:

A = 250 e^(-7.25x10⁻⁴ * 365)

A = 250 e^(-0.7675)

A = 191.87 g

However, the question is the percentage left after 1 year so:

% = (191.87 / 250) * 100

<h2>% = 76.75%</h2><h2>And this is the % of isotope after 1 year</h2>
3 0
3 years ago
Read 2 more answers
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