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anastassius [24]
3 years ago
7

ILL MARK BRAINLIEST FOR REAL ANSWERS

Mathematics
2 answers:
Llana [10]3 years ago
8 0
The answer should be (0, 0).
I'm not sure. Hope it helps.
ryzh [129]3 years ago
7 0
The answer is 0,0 because the linear relationship states that it has to be on a plane of f(x)
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6/8w= -9/3<br><br> solve for w<br><br> pls hurry I need help I will give brainliest
Vesnalui [34]

Answer: w=−4

Step-by-step explanation:

hoped this helped

3 0
3 years ago
Help me please if you can
jolli1 [7]
It is either top left or bottom right, I cannot see the numbers clearly.
3 0
3 years ago
Simplify <br><br><br>pls help ASAP
exis [7]

the bottom is 52y^12

and

the top is 8xy^8*2

6 0
3 years ago
Read 2 more answers
A line is tangent to the circle x^2+y^2=41, at the point (-4,-5)
VashaNatasha [74]
If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
 A general circle's equation is (x-h)^2+(y-k)^2= r^2  
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)

Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0). 

The formula for slope is <u>Y1-Y2</u>
                                   X1-X2
We can break this down with our two points (center and tangent)
  (0,0)    and   (-4,-5)
(X1,Y1) and (X2,Y2)

therefore, we will put the equation as such
<u>0-(-5)= 5</u>  = <em> </em><u><em>5</em></u>
0-(-4)= 4     <em> 4</em>

<em>this is our slope from the center to the point of tangency.</em>

We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to. 

Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
<u>5</u> =  <u>-5</u>  =  <u>-4</u><u>
</u>4     4        5   

Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.

Slope-int      y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept  ( the point where x=0, or where its on the y axis)

now we plug things in
(-4,-5) is our point,
<u>-4</u>  is our slope
5

-5=<u>-4</u>(-4)+b       After we plug things in, solve for b
     5

-5= 3.2+b

-1.8= b  or  b=  <u />1 <u>4</u>
                         5

Now we just need to rewrite our equation with all our components.
(-4.-5) = point
<u>-4</u>  = slope<u>
</u>5
1 <u>4</u> = y-intercept<u>
</u>   5

<em>y=</em><u><em>-4</em></u><em> x+ 1 </em><u><em>4</em></u><em>     This is the equation of the tangent line</em><u>
</u><em>    5         5</em>


Hope that helped
7 0
3 years ago
A factory produces bottled water at a rate of 2,000 cases per hour. They know that 1.14% of the cases must be rejected because a
IRINA_888 [86]
1.14 per 100 or 1.14:100 or \frac{1.14}{100}

\frac{1.14}{100} =  \frac{n}{2000}

I will multiply the numerator by 20 because multiplying by 20 is how 100 became 2000
22.8 cases are rejected per hour.
4 0
3 years ago
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