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vagabundo [1.1K]
3 years ago
12

Which point lies on the line with point-slope equation y-2=5(x-6)

Mathematics
1 answer:
Leviafan [203]3 years ago
6 0

The numbers inside the brackets determine which point lies on the line.

The general formula is

y - h = m(x - k)

The point that lies on the line however is (h,k) both turn to the opposite sign.

So in your case the point is (6,2). I have made a graph to show you that this is true. No other point is possible.

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Where do I put the parentheses:<br>7+3x4-1=39
allsm [11]
(7+3)x(4-2)=39
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3 years ago
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In the figure below, what are k and m ​
DerKrebs [107]

The answer to your question is k and m are both 9

6 0
3 years ago
What is the image of (4,-7) after a reflection over the line y=x
snow_lady [41]

Answer:

(-4,7)

Step-by-step explanation:

solved by graphing

3 0
3 years ago
Find the first five terms of the recursive sequence <br> an=-6an-1 where a1=4.5
grandymaker [24]

Answer:

4.5, -27, 162,-972, 5832

Step-by-step explanation:

The given recursive definition is,

a_n=-6a_{n-1}, a_1=4.5

This will form a geometric sequence with first term 4.5 and common ratio r=-6.

When n=2, we have:

a_2=-6a_1 \\  \implies \: a_2=-6 \times 4.5 =  - 27

When n=3, we get:

a_3=-6a_2 \\  \implies \: a_3=-6 \times  - 27 =  162

When n=4, we get:

a_4=-6a_3 \\  \implies \: a_4=-6 \times 162 =  - 972

When n=5, we get:

a_5=-6a_4 \\  \implies \: a_5=-6 \times  - 972 = 5832

Therefore the first five terms are:

4.5, -27, 162,-972, 5832

3 0
4 years ago
Determine which lines, if any, are parallel or perpendicular. Explain.
Orlov [11]

Answer:

line a and b are parallel, there is no perpendicular lines

Step-by-step explanation:

Looking at the slope of each line, you can identify whether the lines are parallel, perpendicularlar, or neither.

When the slopes are the same, they are parallel.

When the slopes have opposite sign and numerator and denominator flipped, they are perpendicular. Ex. \frac{a}{b} and -\frac{b}{a} are perpendicular slopes.

Finding slope is using the formula: \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

Line a has slope  \frac{3-4}{4-0} = -\frac{1}{4}

Line b also has slope -\frac{1}{4}

Line c has slope 2

Since slope of line a and b are same, they are parallel.

Line c is not perpendicular to line a and b because the slope should have opposite sign and numerator and denominator flipped, which is 4 not 2.

4 0
3 years ago
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