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3 years ago

((Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Mathematics

1 answer:

Vinil7 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

A series is said to be convergent if |r| < 1. Where r is the common ratio of the series.

If |r| ≥ 1 then the geometric series diverges.

3/4 + 4/5 + 5/6

r = 4/5÷3/4 = 4/5×4/3 = 16/15

r = 5/6÷4/5 = 5/6×5/4 = 25/24

In the series, r is greater than 1. So the series is divergent.

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2. Simplify the expression. (x3)(x7)²<br> 1<br> x18<br> x14<br> x126

lisabon 2012 [21]

Step-by-step explanation:

$= ( {x}^{3} ) { ({x}^{7} )}^{2}$

$= {x}^{3} \times {x}^{7 \times 2}$

$= {x}^{3} \times {x}^{14}$

$= {x}^{3 + 14}$

$= {x}^{17}$

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2 years ago

30 PTS. + BRAINLIEST PLS HELP AZAP!!!

Papessa [141]

Answer:

C and E would be your Answer!

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3 years ago

A ferry charges $30 per car plus $5 for each passenger in the car.

ad-work [718]

They have to pay the 30$ fee first then it depends on how many people are coming with you

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3 years ago

Read 2 more answers

Cate solved an inequality to find c, the possible number of cats that a shelter can house. She found that c < 28. Which state

stellarik [79]

Since the number of cats has to be less than 28, a statement could be "the shelter can house no more than 28 cats.

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3 years ago

Read 2 more answers

Kamal wrote the augmented matrix below to represent a system of equations

ra1l [238]

Consider the operation is $R_2\to -3R_2$ .

Given:

The augmented matrix below represents a system of equations.

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

To find:

Matrix results from the operation $R_2\to -3R_2$ .

Step-by-step explanation:

We have,

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

After applying $R_2\to -3R_2$ , we get

$\left[\left.\begin{matrix}1&0&1\\-3(1)&-3(3)&-3(-1)\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-3(-9)\\-2\end{matrix}\right]$

$\left[\left.\begin{matrix}1&0&1\\-3&-9&3\\3&2&0\end{matrix}\right|\begin{matrix}-1\\27\\-2\end{matrix}\right]$

Therefore, the correct option is A.

3 0

3 years ago