Question

Mike and Joey bought identical loaves of bread and packages of bologna. Mike made sandwiches with 5 slices of bologna and had 4 slices of bread left when he ran out of meat. Joey made sandwiches with 4 slices of bologna and had 4 slices of meat when he ran out of bread. How many slices of bread were in each loaf?

Answer 1

Answer:

Mike had 14 slice of bread in his loaf while

Joey had 8 slice of bread in his loaf.

Step-by-step explanation:

We should note that a sandwich is made up of two slice of bread.

that is :

A Sandwich = 2 Slice of bread

and for bologna to be in a sandwich, you will have 2 slice of bread together.

So, For Mike,

2 slice of bread × 5 Sandwich = 10 Slice of bread

Remaining Slice of bread = 4 Slice

Total Slice of bread in Mike loaf = 10 + 4

= 14 slice of bread was in Mike loaf of bread.

For Joey

A sandwich = 2 Slice of bread

2 slice of bread × 4 Sandwich = 8 Slice of bread

Remaining slice of bread = 0

Total slice of bread in joey loaf = 8 slice of bread.

Answer 2

Answer:

The correct answer is 28 slices of bread

Step-by-step explanation:

Let there be BO slices of bologna and BR slices of bread in a package.

Mike use  BO/5  ( 5 slides per sandwich) and he use bread, BR- 4= BO/5 x2  

Joey use (BO-4)/4 and BR=(BO-4)/4 x2

We know BO and BR are the same for each one ,  so we can replace BR in one equation and Isolate BO

((BO-4)/4 x2)- 4= BO/5 x2  

We divide each term by 2  

((BO-4)/4 )- 2= BO/5

BO/4-1 -2=BO/5

BO/4-3=BO/5

BO/4- BO/5=3

5BO-4BO/20=3

1BO/20=3

BO= 3x 20

BO=60

 

and BR=(BO-4)/4 x2

BR=(60-4)/4 x2

BR=(56)/4 x2

BR=14 x 2= 28