Consider a population of frogs. Allele B1 codes for spotted frogs; allele B2 codes for non-spotted frogs. B1 is dominant to B2 .
2 answers:
Answer: (p,q) = (0.27,0.73)
Explanation: In the island, the frequency of B1, which is dominant is: p=0.55 and for B2 is q=0.45. In total, there are 170 frogs.
Individuals with B2 allele in the island:
170*0.45 = 76.5
During the storm, 30 frogs with recessive characteristics went to the island, which means that the population of frogs which has recessive genotype increased, so did its frequency and general population:
New total of frogs: 170 + 30 = 200
New frequency of B2 frogs:
76.5 + 30 = 106.5
q = 0.73
With the frequency of recessive and as p + q = 1,
p = 1 - q
p = 1 - 0.73
p = 0.27
Thus, the new frequencies for B1 and B2 in the island is (0.27,0.73) respectively.
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Answer:
A. If neither parent expresses the trait, but the offspring does, both parents must be heterozygous for the trait.
Explanation:
If neither parents express the trait is because they are heterozygous and the dominant allele is being expressed over the recessive trait. When parents cross they have 25% of having an offspring that expresses the recessive trait, this means the offspring is a recessive homozygous. In the attached example 25% or 1/4 will have a short stem.
