Gravitational potential energy can be given by the equation
PE = mgh
where m is the mass,
g is the gravitational constant 9.81 or 10 depending on rounding
and h is the height
well weight is a force equiavlent to
W= m*g
so comparing that to the potential energy equation, divide the potential energy by the height and you will get weight in Newtons
Try this solution:
if given m=0.15 kg; t₁=20 °C; t₂=100 °C; c=4190 J/(kg*C); q=226*10⁴ J/kg., then
Q=Q₁+Q₂,
where Q₁=cm(t₂-t₁) and Q₂=q*m.
Finally,
Q=cm(t₂-t₁)+qm;
Q=4190*0.15*80+2240000*0.15=386280 J=<u>386.28 kJ</u>.
Answer:
v₂ = 5131.42 m/s
Explanation:
given,
radius of the planet = r₁ = 9.00×10⁶ m
mass of the satellite = m₁ = 68 Kg
orbital radius = r₁ = 8 x 10⁷ m
orbital speed = v₁ = 4800 m/s
mass of second satellite = m₂ = 84.0 kg
orbital radius = r₂ = 7.00×10⁷ m
orbital speed of second satellite = v₂ = ?
using orbital speed of satellite

so,

now,


v₂ = 5131.42 m/s
The orbital speed of second satellite is equal to v₂ = 5131.42 m/s