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gladu [14]
3 years ago
9

Two metal spheres that are initially uncharged are mounted on insulating stands. A negatively charged rubber rod is brought clos

e to, but does not make contact with sphere X. Sphere Y is then brought close to X on the side opposite to the rubber rod. Y is allowed to touch X and then is removed some distance away. The rubber rod is them moved far away from X and Y. What are the final charges on the spheres
Physics
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

Sphere X is positively charged while sphere Y is negatively charged

Explanation:

The method described in the given experiment is known as charging by induction. Charging by induction is a method used to charge an object without actually touching the object to any other charged object

When a negatively charged rubber rod is brought near the uncharged sphere X, charges are induced in the metal sphere. Positive charges are attracted to to the rubber rod whereas negative charges are repelled away from the rod. Since the spheres are mounted on insulated stands, the induced charges remain on the sphere. When sphere Y is made to touch sphere X, the negative charges from X flow into Y leaving it with excess negative charges.  When Y is then removed from X, the excess negative charges are then evenly distributed across the surface of Y. Finally, the rubber rod is moved far way from X leaving X with excess positive charges due to the electrons that have flowed from it into Y.

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A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 25° above the horizo
mars1129 [50]

Answer:

a) y=17.6m

b) v_{x}=39.87m/s\\v_{y}=-28.05m/s

Explanation:

From the exercise we got our <u>initial data</u>

v_{o}=44m/s\\\beta =25\\x=190m

a) To find <u><em>maximum height</em></u> we know that at that point v_{y}=0

v_{y} ^{2} =v_{oy} ^{2} +2a(y-y_{o} )

0=(44sin25)^{2} -2(9.8)y

Solving for y

y=\frac{(44sin25)^{2} }{2(9.8)} =17.6 m/s

b) Since we know that the ball strikes the fairway 190 m away

x=v_{ox}t\\ 190=44cos25t

Solving for t

t=4.76s

Now, we can calculate the speed of the ball in both axes

v_{x}=44cos25=39.87m/s

v_{y}=v_{oy}+at

v_{y}=44sin25-(9.8)(4.76)=-28.05m/s

The <em>negative</em> sign means the direction of the ball at that point.

5 0
4 years ago
3. A very brittle piece of iron metal (C=.44 J/gC) is heated to 200 C and placed
lubasha [3.4K]

Answer:The temperature of a piece of Metal X with a mass m of 95.4g increases from 25.0°C to 48.0°C as the metal absorbs 849 J of heat.

Explanation:

4 0
2 years ago
A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its potential energy (PE) when it is 2.00 m above the grou
zloy xaker [14]

Answer:

1.5288 J

Explanation:

We can use the Energy conversion law

Energy can not be made or destroyed. It can only be converted to another form of energy

Potential Energy (PE) is the energy an object has due to its height of the location

<em>PE = mass * gravitational acceleration * height from the ground</em>

Simply here , lemming had a PE and KE also.  

(g = 9.8 m/s²)

PE = 0.0780 * 9.8  *2

     = 1.5288 J

4 0
3 years ago
what is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?​
timurjin [86]

The initial velocity of go-kart is 2.5 m/s.

<u>Explanation:</u>

Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.

In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.

As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.

Acceleration = \frac{Final velocity -Initial velocity}{Time}

Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,

        -0.5=\frac{-\text {Initial velocity}}{5}

        Initial velocity = 0.5 × 5 = 2.5 m/s.

So the initial velocity of go-kart is 2.5 m/s.

8 0
3 years ago
True or False:In a current, electrons will always flow from negative to positive.
DIA [1.3K]
It should be true: electrons low from negative toward positive to negative toward positive because opposite charges attract each other.

I hope this was correct
3 0
3 years ago
Read 2 more answers
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