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AlladinOne [14]

3 years ago

7

Si unit of small g and G

1 answer:

Mila [183]3 years ago

5 0

Answer:

G

Explanation:

because the Si unite of g is G mean gram

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Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c

Oksana_A [137]

The s<span>tatic charges that are applied to neutral objects by friction, induction or conduction main utilise the creation of electrons or electric charges. Electrons flow forming a current into a specific medium known as a conductor which is mainly due to a significant potential difference between two points.</span>

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3 years ago

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Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of

STatiana [176]

Answer:

$2.27\cdot 10^{49}$

Explanation:

The gravitational force between the proton and the electron is given by

$F_G=G\frac{m_p m_e}{r^2}$

where

G is the gravitational constant

$m_p$ is the proton mass

$m_e$ is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N$

The electrical force between the proton and the electron is given by

$F_E=k\frac{q_p q_e}{r^2}$

where

k is the Coulomb constant

$q_p = q_e = q$ is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N$

So, the ratio of the electrical force to the gravitational force is

$\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}$

So, we see that the electrical force is much larger than the gravitational force.

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3 years ago

Why is it possible for a gas to take the shape of its container?

Sedaia [141]

I believe the answer is A

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3 years ago

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Help i forgot to complete this worksheet

Naily [24]

just search up the answer/ definition to all of them, rephrase into own words, then do the same for examples.

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4 years ago

What is the momentum of a bird with a mass of 0.018kg flying at 15m/s?

Mazyrski [523]

Answer:

0.27 kg-m/s

Explanation:

i believe this is the correct answer

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2 years ago