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3 years ago

8. Write the number in expanded form. 674.281

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

8 0

Answer: expanded factor form would be 6 x 100 + 7 x 10 + 4 x 1 + 2 x 0.1 +8 x 0.01 +1 x 0.001

marysya [2.9K]3 years ago

4 0

600+70+4+.2+.08+.001

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Please help this is so confusing u can have 25 points if u help me

Elina [12.6K]

Step-by-step explanation:

Share 20pounds in the ratio 2:3

Total ratio=2+3=5

2/5×20=8

20-8=12

Sharing 20pounds in that ratio gives 8pounds:12pounds

Share 15cm in the ratio 1:3

Total ratio=1+4=4

¼×15=3.75

15-3.75=11.25

Sharing 15cm in that ratio gives 3.75:11.25

7 0

2 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

2 years ago

0.15, 0.17, 0.19. what is going up by ?

Tpy6a [65]

Answer:

It goes up by 2 each time

Step-by-step explanation:

3 0

3 years ago

A=5/6(B+C) SOLVE FOR C

Shalnov [3]

A = 5/6(B + C)

multiply 6 on both sides

6A = 5(B + C)

divide 5 from both sides

6A/5 = B + C

subtract B from both sides

6A/5 - B = C

3 0

2 years ago

What is the reciprocal of 3 1/5?

aivan3 [116]

if u like it,u can start following me...

5 0

3 years ago

Read 2 more answers