Mass of BaO in initial mixture = 3.50g
Explanation:
Let mass of BaO in mixture be x g
mass of MgO in mixture be (6.35 - x) g
Initially CO_2
Volume = 3.50 L
Temp = 303 K
Pressure = 750 torr = 750 / 760 atm
Applying ideal gas equation
PV = nRT
n = PV / RT
(n)_CO_2 = ((750/760)* 3.50) / 0.0821 * 303
(n)_CO_2 = 0.139 mole
Finally; mole of CO_2
n= PV /RT
((245/760) *3.5) / 303* 0.0821
(n)_CO_2 = 0.045 mole
Mole of CO_2 reacted = 0.139 - 0.045
=0.044 mole
BaO + CO_2 BaCO_3
Mgo + CO_2 MgCO_3
moles of CO_2 reacted = ( moles of BaO + moles of MgO)
moles of BaO in mixture = x / 153 mole
moles of MgO in mixture = 6.35 - x mole / 40
Equating,
x/ 153 +6.35/40 = 0.094
= x/153 + 6.35 / 40 - x/40 =0.094
= x (1/40 - 1153) = (6.35/40 - 0.094)
= x * 10.018464
= 0.06475
mass of BaO in mixture = 3.50g
Answer: <span>B. a nonpolar molecule
</span>Water is a molecule made of two hydrogens and one oxygen. Water structure looks like a mickey mouse which makes it polar.
A polar compound will attract others polar molecules. That cause a polar substance will have much more solubility in water than non-polar substance like oil. Since the substance is not dissolved in water, it is more likely for it to be a non-polar molecule.
<h3>
Answer: Choice A) 0-7</h3>
Explanation:
If the pH is between 0 and 7, then we have an acid.
If the pH is between 7 and 14, then we have an alkaline base.
If pH = 7, then it's neutral.