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murzikaleks [220]
3 years ago
8

Which of the following represents a chemical change?

Chemistry
1 answer:
Snezhnost [94]3 years ago
3 0
The answer is B.) Freezing of water
You might be interested in
Please help asap and thank you
natulia [17]

Answer:

Metamorphic rock

Explanation:

metamorphic rocks do not get hot enough to melt they just get denser if they did they would become igneous rocks.

7 0
3 years ago
What is the percent, by mass, of water in MgSO4.2H20
iris [78.8K]

Answer:51.1%

Explanation:

Mass percent : It is defined as the mass of the given component present in the total mass of the compound. Formula used : First we have to calculate the mass of  and . Mass of  = 18 g/mole Mass of  = 7 × 18 g/mole = 126 g/mole Mass of  = 246.47 g/mole Now put all the given values in the above formula, we get the mass percent of  in . Therefore, the mass percent of  in  is, 51.1%

8 0
2 years ago
An electron is moving northward in a magnetic field. the magnetic force on the electron is toward the northeast. what is the dir
sweet-ann [11.9K]
The direction of the magnetic field would be going up.
8 0
3 years ago
How do magnets move objects?​
shutvik [7]

Answer: Magnets have a force which is known as no contact force. This force tries to attract the metallic objects near it, which makes it move.

Explanation:

7 0
3 years ago
What is the molarity of a 17.0% by mass solution of sodium acetate, NaC2H3O2 (82.0 g/mol), in water? The density of the solution
sattari [20]

Answer:

[NaCH₃COO] = 2.26M

Explanation:

17% by mass is a sort of concentration. Gives the information about grams of solute in 100 g of solution. (In this case, 17 g of NaCH₃COO)

Let's determine the volume of solution, by density

Mass of solution / Volume of solution = Solution density

100 g / Volume of solution = 1.09 g/mL

100 g / 1.09 g/mL = 91.7 mL

17 grams of solute is contained in 91.7 mL

Molarity (M) = Mol of solute /L of solution

91.7 mL / 1000 = 0.0917L

17 g / 82 g/m = 0.207 moles

Molariy = 0.207 moles / 0.0917L → 2.26M

4 0
3 years ago
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