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vodomira [7]
3 years ago
11

Lauren walks 100m in half a minute. What must her speed have been to travel this distance?

Chemistry
1 answer:
tester [92]3 years ago
4 0

Answer:

10/3 m/s. v=d/t. so 100/30 = 10/3

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The value of the metal in 2p coins, made in 1991 is now worth 3.3p.
Studentka2010 [4]

The coins in 1991 had more copper in them compared to the coins today. So, that is why it worth 3.3p.  
8 0
3 years ago
If the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10, how much does the pH change:
andreev551 [17]

Answer:

The pH changes by 2.0 if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

Explanation:

To solve this problem we use the<em> Henderson-Hasselbach equation</em>:

  • pH = pKa + log [A⁻]/[HA]

Let's say we have a weak acid whose pKa is 7.0:

  • pH = 7.0 + log [A⁻]/[HA]

If the [A⁻]/[HA] ratio is 10/1, we're left with:

  • pH = 7.0 + log (10/1)
  • pH = 7.0 + 1
  • pH = 8.0

Now if the ratio is 1/10:

  • pH = 7.0 + log (1/10)
  • pH = 7.0 - 1
  • pH = 6.0

The difference in pH from one case to the other is (8.0-6.0) 2.0.

<em>So the pH changes by 2.0</em> if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

<u>Keep in mind that no matter the value of pKa, the answer to this question will be the same.</u>

3 0
3 years ago
Due Tomorrow!<br><br> What is [OH-] of a solution<br> with a pH of -1.0? <br><br> Answer in M
Margaret [11]
M IS A LETTER but N is a letter
8 0
2 years ago
A prototype is usually different from the final product
Assoli18 [71]
True. The prototype is usually the "rough draft" the figure out what needs fixed or upgraded before they make the final product "final draft". Hope that helped!
7 0
3 years ago
The decomposition of NH4HS is endothermic: NH4HS(s)⇌NH3(g)+H2S(g) Part A Which change to an equilibrium mixture of this reaction
shepuryov [24]

Explanation:

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

As the given reaction is as follows.

       NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)

(a)  When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.

Thus, formation of H_{2}S will increase.

  • (b)  When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.

Hence, formation of H_{2}S will decrease with decrease in volume.

  • When we increase the mount of NH_{4}HS then equilibrium will shift in the direction of decrease in concentration that is, in the forward direction.

Thus, we can conclude that formation of H_{2}S will increase then.

3 0
3 years ago
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