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4 years ago

What is the solution for this inequality? 8x<-32

Mathematics

2 answers:

Tju [1.3M]4 years ago

7 0

Step-by-step explanation:

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Mandarinka [93]4 years ago

4 0

Answer:

8x<-32

x<4

Step-by-step explanation:

divide both of these numbers by 8

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Write the equation of a line that is perpendicular to x=-6x=−6x, equals, minus, 6 and that passes through the point (-1,-2)(−1,−

Alja [10]

9514 1404 393

Answer:

y = -2

Step-by-step explanation:

The given line is a vertical line, so a perpendicular line will be a horizontal line. It will have an equation of the form ...

y = constant

In order for the line to go through the given point, the constant in the equation must be the same as the y-coordinate of the point: -2.

Your perpendicular line is ...

y = -2

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3 years ago

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A price of a motorcycle is Rs 175000. The year rate of deprecation is 4%. Find the price of motorcycle after 3 years

sasho [114]

$FV = PV (1 - \frac{r}{100})^n\\FV = 175000 (1 - \frac{4}{100})^3\\$

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2 years ago

Find an equation of the line described below. Write the equation is slope-intercept from ( solved for y), when possible. Through

Sladkaya [172]

Answer:

The equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

Step-by-step explanation:

Given that the line passes through the point (5,4).

As the line is parallel to the x-axis, the slope of the line would be zero.

And we have point (5,4) from which the line is passing.

So, $x_1=5\ ,\ y_1=4\ and\ m=0$

The equation of the line passing through point $(x_1,y_1)$ is

$y-y_1=m(x-x_1)\\y-4=0(x-5)\\y-4=0\\y=4$

So, the equation of the line that is passing through the point (5,4) and is parallel to x-axis would be $y=4$

4 0

4 years ago

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

Note: Since you missed to mention the the expression of the function $p(x)$ . After a little research, I was able to find the complete question. So, I am assuming the expression as $p(x)=x^4-9x^2-4x+12$ and will solve the question based on this assumption expression of $p(x)$ , which anyways would solve your query.

Answer:

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say $p(x)$ , $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ , we must have to evaluate $p(x)$ for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$