Simplify –3 – 1 what is the answer to this ?

There 8 black dogs there 4 fewer black dogs than brown dogs. how many brown dogs are there

Colt1911 [192]

There are 12 brown dogs

3 0

3 years ago

Read 2 more answers

Missing pattern 24,21, blank 15 blank ,blank

never [62]

To figure out this pattern, let's see if there's a constant rule that this sequence follows.
From 24 to 21, you're subtracting 3.
Let's try n-3, and fill in the blanks as we go.
24 - 3 = 21.
21 - 3 = 18.
18 - 3 = 15.
15 - 3 = 12.
12 - 3 = 9.
It seems that n-3 works as a rule, so your rule is:
N-3.
The missing blanks are:
18, 12, and 9.
I hope this helps!

8 0

3 years ago

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Simplify sin θ / square root 1 - sin^2 θ

Soloha48 [4]

Recall that

$\cos^2\theta+\sin^2\theta=1$

which means

$\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{\sqrt{\cos^2\theta}}$

Now, $\cos\theta$ could be positive or negative, which means $\sqrt{\cos^2\theta}=|\cos\theta|$ . If we specifically knew the sign of $\cos\theta$ was positive, then we can simplify and write

$\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{\cos\theta}=\tan\theta$

or if it's negative,

$\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{-\cos\theta}=-\tan\theta$

7 0

4 years ago

The two-way table shows the distribution of gender to favorite film genre for the senior class at Mt. Rose High School.

Studentka2010 [4]

Answer:

The second statement is correct

Step-by-step explanation:

Hello!

The table shows the information of the favorite film genre of the students of the class regarding their gender.

You have to prove which statement is correct:

1)The probability of randomly selecting a student who has a favorite genre of drama and is also female is about 17 percent.

If you chose a student at random, you need to calculate the probability of its favorite genre being "Drama" (D) and the student being female (F), symbolically: P(D∩F)

To do so you have to divide the number of observed students that are female and like drama by the total number of students:

P(D∩F)= $\frac{24}{240}= \frac{1}{10} =0.10$

This means that the probability of choosing a student at random and it being a female that likes drama is 10%.

This statement is incorrect.

2) Event F for female and event D for drama are independent events.

Two events are independent when the occurrence of one of them doesn't affect the probability of occurrence of the other one.

So if F and D are independent then:

P(F)= P(F|D)

-or-

P(D)=P(D|F)

The probability of the event "Female" is equal to $P(F)= \frac{Total females in the class}{n} = \frac{144}{240} = \frac{3}{5}= 0.6$

The probability of the event "Drama" is:

$P(D)= \frac{Total students that like "Drama"}{n}= \frac{40}{240}= \frac{1}{6}= 0.166$

$P(F|D)= \frac{P(FnD)}{P(D)}= \frac{\frac{1}{10} }{\frac{1}{6} }= \frac{3}{5} = 0.6$

As you can see P(F)= 0.6 and P(F|D)= 0.6 so both events are independent.

This statement is correct.

3) The probability of randomly selecting a male student, given that his favorite genre is horror, is 16/40

This is a conditional probability, you already know that the student likes horror movies (H), and out of that group you want to know the probability of the student being male (M):

$P(M|H)= \frac{number of male students that like horror movies}{total students that like horror movies}= \frac{16}{38}= \frac{8}{19} = 0.42$