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2 years ago

A seven-sided number cube with sides numbered 1-7 is rolled. what is the probability that a 4 or an odd number is rolled.

Mathematics

1 answer:

jeka57 [31]2 years ago

8 0

There’s a 1/7 chance it would roll a 4.

There’s a 4/7 chance it would roll an odd number.

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Consider the equation 4x=8.<br> Which value could be substituted x to make the equation TRUE?

const2013 [10]

X=2 (4 x 2 = 8) so 2 is the answer

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3 years ago

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Match the inequality with its line graph.

Flura [38]

Answer:

Here, answer is given in form of 4 figure labelled with inequality

Step-by-step explanation:

Given inequality are

A). $2x>(-6)$

B). $6+x\leq 3$

C). $x-4$

D). $-x-5\leq (-2)$

For matching with givens graph:

Simplifying...

A). $2x>(-6)$

Divide 2 on both sides

$x>(-3)$

B). $6+x\leq 3$

Add (-6) on both side.

$6+x+(-6)\leq 3+(-6)$

$x\leq(-3)$

C). $x-4$

Add (4) on both side.

$x-4+4$

$x$

D). $-x-5\leq (-2)$

Multiple (-1) on both side

$+x+5\geq (+2)$

Note : Change of inequality sign due to multipication of negative number

Add (-5) on both side.

$x\geq (-3)$

Here, Answer is given in form of 4 figure labelled with inequality

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2 years ago

Write the ratio 15:25 as a fraction in simplest form

jenyasd209 [6]

Answer:

15:25 simplified = 3:5

Step-by-step explanation:

1st step= find out what is the highest command factor

We know it is 5

So we do 15 divided by 5 which is 3

And 25 divided by 5 which is 5

So the answer is 3:5

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3 years ago

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vova2212 [387]

14r+20<14r+16 or 8−10r>15−9r

14r+20<14r+16

14r+20−14r<14r+16−14r(Subtract 14r from both sides)

20<16

20−20<16−20(Subtract 20 from both sides)

0<−4

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−10r+8>−9r+15(Simplify both sides of the inequality)

−10r+8+9r>−9r+15+9r(Add 9r to both sides)

−r+8>15

−r+8−8>15−8(Subtract 8 from both sides)

−r>7

−r/−1 > 7/−1(Divide both sides by -1)

r<−7

Ur answer is:

r < - 7 OR 0 < - 4

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3 years ago

Writing an equation and drawing its graph to model a real-world situation: Advanced

Leokris [45]

Assuming that rent will always be constant.
C= 250×S+ 7500 for S>0

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