Question

An apparatus like the one Cavendish used to find G has large lead balls that are 7.2 kg in mass and small ones that are 0.053 kg. The center of a large ball is separated by 0.063 m from the center of a small ball. Mirror m Light source M r κ The Cavendish apparatus for measuring G. As the small spheres of mass m are attracted to the large spheres of mass M, the rod between the two small spheres rotates through a small angle. Find the magnitude of the gravitational force between the masses if the value of the universal gravitational constant is 6.67259 × 10−11 N m2 /kg2 . Answer in units of N.

Answer 1

Answer:

$6.41537\times 10^{-9}N$

Explanation:

Given that $G=6.67259\times 10^{-11}Nm^2/kg$, we can use Newton's Universal law of gravitation to determine the magnitude of the gravitational force as:

$F=G\frac{m_1m_2}{r^2}\\\\\\=G=6.67259\times 10^{-11}Nm^2/kg\frac{7.2kg\times 0.053kg}{(0.063m)^2}\\\\\\=6.41537\times 10^{-9}N$

Hence, the magnitude of the gravitational force between the masses is $6.41537\times 10^{-9}N$