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harkovskaia [24]
3 years ago
15

Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls f

rom the top of a shelf to the ground?​
Physics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

The force is of the weight <u>862,4 Newtons.</u>

<u></u>

Explanation:

We have the formula:

w = m * g

Data:

w = weight = ¿?

m = mass = 88 kg

g = gravity = 9,8 m/s

Replacing according formula:

w = 88 kg * 9,8 m/s

Resolving:

w = 862,4 N

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A ball is thrown 20.0 m/s at an angle of 40.0° with the horizontal. Assume the ball is thrown at ground level.
TEA [102]
The ball's horizontal component of velocity (ie it's horizontal speed) is 20 cos 40degrees. Without knowing the distance of the ball to the wall it's difficult to go further ...
8 0
3 years ago
A thin insulating rod is bent into a semicircular arc of radius a, and a total electric charge Q is distributed uniformly along
storchak [24]

Answer:

v = \frac{kQ}{a}  

Explanation:

We define the linear density of charge as:

\lambda = \frac{Q}{L}

     Where L is the rod's length, in this case the semicircle's length L = πr

The potential created at the center by an differential element of charge is:

dv = \frac{kdq}{r}

          where k is the coulomb's constant

                     r is the distance from dq to center of the circle

Thus.

v = \int_{}^{}\frac{kdq}{a}  

v = \frac{k}{a}\int_{}^{}dq

v = \frac{kQ}{a}     Potential at the center of the semicircle

4 0
3 years ago
How much power is needed to lift the 200-N object to a height of 4 m in 4 s?
Vitek1552 [10]

Answer: 2000 watts

Explanation:

Given that,

power = ?

Weight of object = 200-N

height = 4 m

Time = 4 s

Power is the rate of work done per unit time i.e Power is simply obtained by dividing work by time. Its unit is watts.

i.e Power = work / time

(since work = force x distance, and weight is the force acting on the object due to gravity)

Then, Power = (weight x distance) / time

Power = (200N x 4m) / 4s

Power = 8000Nm / 4s

Power = 2000 watts

Thus, 2000 watts of power is needed to lift the object.

3 0
4 years ago
Superman does an exhibition run at a track meet. When he runs the 200 m
Ber [7]

Answer:

6.32s

Explanation:

Given parameters:

Length of track and distance covered  = 200m

Acceleration  = 10m/s²

Unknown:

Time taken to cover the track  = ?

Solution:

To solve this problem, we apply one of the motion equations as shown below:

       S  = ut + \frac{1}{2} at²  

S is the distance covered

t is the time taken

a the acceleration

u is the initial velocity

The initial velocity of Superman is 0;

 So;

     S  =  \frac{1}{2} at²  

        200  =  \frac{1}{2} x 10 x t²  

          200  = 5t²  

            t²  = 40

            t  = 6.32s

5 0
3 years ago
If you run at 12 m/s fr 15 minutes, how far will you go
notsponge [240]

Answer:

180m

Explanation:

We can use the formula [ d = st ].

12 * 15 = 180m

Best of Luck!

4 0
3 years ago
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