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baherus [9]
3 years ago
6

Ohh by asks zh a. Mans jks shall snnkkksajsiaoksoo

Physics
2 answers:
Ahat [919]3 years ago
5 0

Answer:

han

Explanation:

jabxhxuxjx

zhannawk [14.2K]3 years ago
4 0

Answer: fREe pOINtS

Explanation:

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A rock is thrown horizontally at 10.0m/s off of a 150m sheer cliff. What is the range?
inn [45]

Answer:20

Explanation:

7 0
3 years ago
Read 2 more answers
Suppose the U.S. national debt is about $14 trillion. If payments were made at the rate of $3,500 per second, how many years wou
andreyandreev [35.5K]

Answer:

It will take 126.84 years to pay off the debt

Explanation:

Total debt = $14,000,000,000,000.00

Paid $3,500 per second

Number of seconds to pay off the debt will be:

14 ×10^12 /3500

Number of seconds = 4× 10^9 seconds

Converting seconds to year:

I second = 3.171 ×10^-8 calendar year

Therefore, number of years it will take to pay off $14 Trillion =( 4 ×10^9 ) × ( 3.171 × 10^-8)

Number of years = 126.84 years

5 0
3 years ago
Which scale has 100 divisions from when the temperature when water freezes to the temperature when water boils
Westkost [7]
The Celsius scale (^{\circ} C).

In the Celsius temperature scale, the temperature at which water freezes is set conventionally at 0^{\circ}C, while the temperature at which the water boils is set at 100^{\circ}C. The Celsius degree is then defined as the unit corresponding to 1/100 of this time interval, between the temperature of freezing and boiling of the water.
8 0
3 years ago
How do particles move differently in transverse waves and in surface water waves?
elixir [45]
The particles always move parallel and perpendicular to the waves. The waves which are in the water moves a circle. Both up and down and back and forth.

Good luck :)
3 0
3 years ago
As a quality test of ball bearings, you drop bearings (small metal balls), with zero initial velocity, from a height of 1.94 m i
11Alexandr11 [23.1K]

Answer:

The average acceleration of the bearings is 0.77\times10^{3}\ m/s^2

Explanation:

Given that,

Height = 1.94  m

Bounced height = 1.48 m

Time interval t=14.86\times10^{-3}\ s

Velocity of the ball bearing just before hitting the steel plate

We need to calculate the velocity

Using conservation of energy

mgh=\dfrac{1}{2}mv^2

Put the value into the formula

9.8\times1.94=\dfrac{1}{2}\times v^2

v=\sqrt{2\times9.8\times1.94}

v=6.166\ m/s

Negative as it is directed downwards

After bounce back,

We need to calculate the velocity

Using conservation of energy

mgh=\dfrac{1}{2}mv^2'

Put the value into the formula

9.8\times1.48=\dfrac{1}{2}\times v^2'

v'=\sqrt{2\times9.8\times1.48}

v'=5.38\ m/s

We need to calculate the average acceleration of the bearings while they are in contact with the plate

Using formula of acceleration

a=\dfrac{v-v'}{t}

Put the value into the formula

a=\dfrac{5.38-(-6.166)}{14.86\times10^{-3}}

a=776.98\ m/s^2

a=0.77\times10^{3}\ m/s^2

Hence,The average acceleration of the bearings is 0.77\times10^{3}\ m/s^2

6 0
3 years ago
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