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svet-max [94.6K]
3 years ago
5

What is an attribute of a fractional equation?

Mathematics
2 answers:
Mariana [72]3 years ago
6 0

Answer:

<h2>There is a variable in the denominator of at least one involved fraction.</h2>

Step-by-step explanation:

The actual definition of a fractional equation could be:

\frac{a}{x}+\frac{b}{x+1}=c

In words, fractional equations are those which has variables in the denominator of a fractional term, that doesn't mean that all fractions must have a unknown denominator, but at least one of the denominators should have a variable.

Therefore, according to its definition, the right answer is third option.

<em>In addition, other options don't make sense, multiple variables is not necessarily the case for fractional equations. Similarly, not all denominators must have variables. And, having variable only in the numerators don't define the equation as fractional.</em>

kkurt [141]3 years ago
3 0

its either a half or part of what its worth

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Here’s a graph of a linear function. Write the equation that describes that function
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Answer:

y=3/2x+2

Step-by-step explanation:

Slope is 3/2, y intercept is 2

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3 years ago
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From the airport hanger H, an areoplane A is 18km away on the bearing of 115° while another aeroplane B is 29km away on a bearin
maks197457 [2]

The difference in distance between Aero plane A and B is; 34.67 km

<h3>How to calculate bearing?</h3>

To get the bearing;

∠H = (115 - 90) + (270 - 203)

∠H = 92°

Then, we will use cosine rule to get the distance between both Planes A and B.

d_ab = √(18² + 29² - 2(18 * 29) * cos 92)

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Read more about bearing at; brainly.com/question/22518031

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6 0
1 year ago
Need solved fast! I can’t do it!!
sergeinik [125]

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<u>Please read below.</u>

Step-by-step explanation:

The instructions were followed, horizontal or vertical path and never diagonal:

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3 years ago
Let u = &lt;-9, 4&gt;, v = &lt;8, -5&gt;. Find u - v. <br> URGENT
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To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle

the subtraction is simply

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So, in your case, we have

\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle

3 0
3 years ago
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