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Nata [24]
3 years ago
14

In pea plants, red flowers and round pollen are known to be recessive traits. In a dihybrid cross experiment, lots of plants wit

h red flowers and round pollen are found in the F2 generation. How is this possible?
The genes for flower color are linked to pea shape, but not pollen shape.
The genes for flower color and pollen shape are found on different chromosomes.
The genes for flower color and pollen shape are linked.
Multiple genes control the traits for flower color and pollen shape.
Biology
1 answer:
densk [106]3 years ago
7 0

Answer:

The genes for flower color and pollen shape are linked.

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How does sympatric speciation differ from allopatric speciation?
Lena [83]

Symaptric speciation is the formation of new species in populations that live in the same geographic area, while allopatric speciation occurs when the population is separated by a geographcial area. So, according to this: The difference between the sympatric speciation and the allopatric speciation is that sympatric speciation involves a behavioral barrier, while allopatric speciation involves a physical barrier.

3 0
2 years ago
PLEASE solve number 1 and 2 because i don’t get it , don’t mind my answers
Readme [11.4K]

Answer:

1) RNA strand =  <em>UCA  GCA  AAU</em>

<em>2) </em>Amino acids:   Asparagine       Arginine             Stop

                            (ASN)               (ARG)              (STOP)

Explanation:

Some theory that you need to know to answer the question:

Each tRNA has two important sites. One of them that couples with the codon of the mRNA molecule, named <em>anticodon</em><em>.</em> The other site couples with an amino acid through the action of the aminoacyl-tRNA synthase enzyme. The whole complex, amino acid + enzyme + tRNA is named aminoacyl-tRNA. Considering that there are twenty amino acids available, there are also twenty complexes of aminoacyl-tRNA, one for each amino acid.  

tRNA allows amino acids to align according to the nucleotidic sequence in the mRNA molecule.  

Once the new amino acid joins the growing peptidic chain, the binding between the amino acid and the tRNA molecule breaks. The tRNA is now free to join another amino acid and repeat the cycle.  

Now, to fill in the boxes, you need to pay attention to two things:

• <u>Anticodon</u>: In this box, you need to place the sequence of bases that pairs with the mRNA codon.  

• <u>Amino Acid</u>: In this box, you need to place the amino acid that is codified by the<u> mRNA </u>codon.  

For instance, let us say that the codon of mRNA is CUC. The anticodon for this sequence is GAG (because guanine joins cytosine and adenine joins uracyl).  

The amino acid places on the 3´extreme of the tRNA molecule will be the one that is codified by the codon, NOT the anticodon. So, as the codon is CUC, the amino acid will be Leucine, Leu. Do not use the anticodon GAG to fill these boxes. Remember that tRNA is translating information carried by the mRNA, so we need to use this information to grow the protein.

<em />

1)

Strand of DNI  →  AGT  CGT  TTA

  • Each of these letters are bases → Adenine, A - Guanine, G - Thymine, T - Cytocine, C
  • Each of these three-lettered groups are codons.

So, we need to pair these bases, knowing that:

Adenine (A) and guanine (G) derive from purines, while Thymine (T) Uracile (U), and Cytosine (C) derive from Pyrimidines.  

In the DNA molecule, Adenine (Purine) always pairs with Timine (Pyrimidine), while Guanine (Purin) forms pairs with Cytosine.

In the RNA molecule,<em> Adenine is paired with Uracil, U. </em>So, whenever there is an Adenine in the DNI strand, it pairs with Uracil of RNA strand. If there is a Thymine in the DNI strand, it pairs Adenine of the RNA strand. And, as always, Guanine pairs with Cytosine.

  • A ⇒ U
  • T ⇒ A
  • G ⇔ C

Knowing how to pair bases, we can fill the RNA molecule boxes.

  • Strand of DNI  →  AGT                   CGT              TTA
  • <em>Strand of RNA →  UCA                  GCA              AAU</em>

<em>                                      A ⇒ U              C ⇒ G            T ⇒ A</em>

<em>                                     G ⇒ C               G ⇒ C            T ⇒ A</em>

<em>                                     T ⇒ A                T ⇒ A            A ⇒ U</em>

2)

Now we need to translate these new codons of mRNA to amino acids.

<em>To fill the boxes you should have a genetic code chart to see the codons that codify for each amino acid. </em>

Codon:                 AAU                 CGA                UAG

Amino acids:   Asparagine       Arginine             Stop

                            (ASN)               (ARG)              (STOP)

<em>The new protein is synthesized from the amino terminus to the carboxy terminus of the mRNA molecule. The added amino acids to the chain are coded by a codon formed by three bases in the mRNA. mARNs also have a start and end codon that are the signals of the synthesis initiation and finish. When the ribosome reaches a stop codon, protein synthesis is over.  </em>

<em />

8 0
3 years ago
Prokaryotic cells do not contain many of the organelles that eukaryotic cells have. Prokaryotic cells do have a primitive form o
Kaylis [27]

Answer:

Figure 1. A typical prokaryotic cell contains a cell membrane, chromosomal DNA that is concentrated in a nucleoid, ribosomes, and a cell wall. Some prokaryotic cells may also possess flagella, pili, fimbriae, and capsules.

please give brainlist

hope this helped.....

7 0
3 years ago
Which statement best summarizes the importance of meiosis to reproduction?
Marrrta [24]
Where are the statements, huh wait what
6 0
3 years ago
Which of the following correctly organizes these genetic terms in order from smallest to largest
Andreas93 [3]

Answer:

Can you list the terms?

Explanation:

3 0
3 years ago
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