Answer:
(2) B
Step-by-step explanation:
According to the graph
p(2, 3) so (-b, a) is (-3, 2)
So B is right
Hat point in the feasible region maximizes the objective function
<span>constraints: </span>
<span>x>=0 </span>
<span>y>=0 </span>
<span>-x+3>=y </span>
<span>y<=1/3 x+1 </span>
<span>Objective function: C=5x-4y </span>
<span>1. Region limited by : </span>
<span>x>=0 </span>
<span>y>=0 </span>
<span>x + y <= 3 </span>
<span>is the interior of rectangle triangle </span>
<span>of summits (0,0), (0,3)and (3,0) </span>
<span>if we add the constraint </span>
<span>y <= 1/3 x + 1 </span>
<span>it's the part in the triangle below this line : </span>
<span>the summits are (0,0) , (0,1) , (3,0) </span>
<span>and the intersection point of </span>
<span>line L of equation : y = x/3 + 1 and the hypotenuse </span>
<span>of the triangle (equation x+y = 3) </span>
<span>let's solve this : </span>
<span>3 - x = x/3 + 1 </span>
<span>4x/3 = 2 </span>
<span>x = 3/2 and y = 3/2 </span>
<span>now the Criteria : C = 5x - 4y </span>
<span>are lines parallel to line of equation </span>
<span>5x - 4y = 0 </span>
<span>or </span>
<span>y = (5/4)x </span>
<span>so C is maximum at an edge of the domain : </span>
<span>points are </span>
<span>O ( 0 ,0) </span>
<span>A( 3 , 0) </span>
<span>B ( 0 ; 1) </span>
<span>D ( 3/2 ; 3/2) </span>
<span>criteria is C = 5x - 4y </span>
<span>C (A) = 5*3 - 4*0 = 15 </span>
<span>C(B) = 5*0 - 4*1 </span>
<span>C(D) = 5* (3/2) - 4*(3/2) = 3/2 </span>
<span>so C is max at point A(3 ; 0)</span>
They should be points (-1.5, 0), (-6, 9), and (3, -9).
13x[4+(9+2)]
13x[4+11]
13x[15]
195
