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3 years ago

The first line drug choice for a previously health adult patient diagnosed with community acquired pneumonia would be

1 answer:

6 0

Community acquired pneumonia is caused by a bacteria pathogen called streptococcus pneumoniae. Pneumonia is an infection that causes the inflammation of the air sacs in one or both lungs. The air sacs maybe filled with fluid or pus , resulting to cough with pus, fever, chills and difficulty in breathing. The first line drug for an adult diagnosed with community acquired pneumonia would be Azithromycin. Azithromycin is an antibiotic used to treat many bacterial infections.

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Some neurons enable you to grasp objects by relaying outgoing messages to the muscles in your arms and hands. these neurons are

densk [106]

The correct answer is known as a "motor neuron".

A motor neuron or also known as a motoneuron is described as a neuron whose cell body is placed inside the motor cortex, brainstem or the spinal cord, and whose axon initiatives to the spinal cord or the exterior of the spinal cord to immediately or not directly manage effector organs, specifically muscle mass and glands.

8 0

3 years ago

in which mode of reproduction do embryos develop inside the mother’s body using an egg yolk for nourishment ?

nataly862011 [7]

Answer:

Ovoviviparous

Explanation:

Embryos develop inside the mother's body using an egg yolk for nourishment is a mode of reproduction called ovoviviparity.

If this helped you, Brainliest is appreciated.

7 0

3 years ago

An igneous rock is found on the ground and has no identifiable crystals. What is the most likely origin of this rock?molten mate

quester [9]

The answer would be: Molten material that cooled quickly.

Igneous rocks are formed by the cooling of molten material. So we can cross out the last two choices. The rock has no identifiable crystals so it is most likely an Extrusive igneous rock. They form on the surface where they cool quickly.

Those that form underground are called intrusive rocks. They cool slowly allowing enough time for crystal formation.

4 0

3 years ago

Read 2 more answers

4) A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality)

docker41 [41]

Answer and Explanation:

A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality).

The F1 females are testcrossed, producing these offspring: groucho 518 rough 471 groucho, rough 6 wild-type 5 1000 a) What is the linkage distance between the two genes? B) Plot the genes on a map c) If the genes were unlinked and the F1 females were mated with the F1 males, what would be the offspring in the F2 generation?

1st cross:

Parental) grogro ro+ro+ x gro+gro+ roro

F1) gro+gro ro+ro

2nd cross:

Parental) gro+gro ro+ro x grogro roro

Gametes) gro+ro+ gro ro

gro+ro gro ro

gro ro+ gro ro

gro ro gro ro

Punnet square)

gro+ro+ gro+ro gro ro+ gro ro

gro ro gro+gro ro+ro gro+gro roro grogro ro+ro grogro roro

F2)

0.518 grogro ro+ro (518 individuals)

0.471 gro+gro roro (471 individuals)

0.006 grogro roro (6 individuals)

0.005 gro+gro ro+ro (5 individuals)

Total number of individuals 1000

Note: These frequencies were calculated dividing the number of individuals belonging to each genotype by the total number of individuals in the F2.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.

In the exposed example we might verify which are the recombinant gametes produced by the F1 di-hybrid, and we can recognize them by looking at the phenotypes with lower frequencies in the progeny.

By performing this cross we know that the phenotypes with lower frequencies in the progeny are groucho, rough and wild-type. So the recombinant gametes are gro+ro+ and gro ro, while the parental gametes are gro+ro and gro ro+.

So, the genotype, in linked gene format, of the double heterozygote individual in the F1 is gro+ro/gro ro+.

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes for which one of every 100 meiotic products results in a recombinant product.

The recombination frequency is:

P = Recombinant number / Total of individuals

P = 6 + 5 / 1000

P = 11 / 1000

P = 0.011

The genetic distance between genes, is 0.011 x 100= 1.1 MU.

Genetic Linkage Map:

Parental Phenotypes)

-----gro+------ro---- -----gro------ro+----

----- gro ------ro---- ---- gro------ ro ----

Recombinant phenotypes)

-----gro+------ro+---- -----gro------ro----

----- gro ------ ro---- -----gro------ro----

If the genes were unlinked and the F1 females were mated with the F1 males, the offspring in the F2 generation would have been

4/16 = 1/4 gro+gro ro+ro

4/16 = 1/4 gro+gro roro

4/16 = 1/4 grogro ro+ro

4/16 = 1/4 grogro roro

Their phenotypic frequencies would be 1:1:1:1 related.

7 0

3 years ago

During which period did the presence of stromatolites decline?

KIM [24]

The period during which the presence of stromatolites decline is the Proterzoic period. Stromatolites are widely distributed sedimentary structures consisting of laminated carbonate or silicate rocks, produced over geologic time by the trapping, binding, or the precipitating of sediment by groups of microorganisms, primarily cyanobacteria.

6 0

3 years ago

Read 2 more answers