Answer:
<h2>
<em>1</em><em>1</em><em>y</em><em>+</em><em>1</em><em>6</em></h2>
<em>Solution</em><em>,</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
Answer: 30 percent of 20 is 6.
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Step-by-step explanation:
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(n/100) * 20 = 6 ?
Solve for "n" .
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Divide each side of the equation by "20" :
{ (n/100) * 20 } / 20 = 6 / 20 ;
to get:
n/100 = 6/20 ;
↔ 6/20 = n/100 ; solve for "n" ;
Look at the denominators:
20 * ? = 100 ?
100/ 20 = ? ;
100/20 = 5 ;
So, 20 * " 5" = 100 ;
Then 6* 5 = "n" (for the numerator, "n"; in : "n /100" ) ;
→ 6 * 5 = 30 ;
→ n = 30 .
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Answer: 30 percent of 20 is 6.
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A) A (1,-1)
b) P' (3,1)
c) Rule: (x, y) → (x + 2, y - 1)
Answer:
a. 16π cm²
b. 24π cm²
c. 33 1/3π cm²
d. 64π-128 cm²
e. 144π-288 cm²
Step-by-step explanation:
To find area of shaded region, find area of whole circle then divide the area where you're left with the area of the shaded region. For the problems with the triangles you find the area of the triangle then subtract that from a fourth of the area of the circle.
Area of a circle = πr²
a.
r=8cm
Area of circle=64π cm²
Shaded region=16π cm²
b.
r=12cm
Area of circle=144π cm²
Shaded region=24π cm²
c.
r=10cm
Area of circle=100π cm²
Shaded region=33 1/3π cm²
d.
r=16cm
Area of circle=256π cm²
Area of triangle=128 cm²
Shaded region=64π-128 cm²
e.
r=24
Area of circle=576π cm²
Area of triangle=288 cm²
Shaded region=144π-288 cm²
