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uranmaximum [27]
4 years ago
13

What three consecutive even numbers add up to 102?

Mathematics
2 answers:
Nookie1986 [14]4 years ago
8 0
The answer to this question is 32,34,36
Daniel [21]4 years ago
6 0
So first you have to understand what consecutive numbers are.
Consecutive numbers are numbers like 4, 6, 8, 10, or 16, 18, 20. 

So let's set up an equation, using x as the first consecutive number. 
x + x + 2 + x + 4 = 102
Then simplify:
3x + 6 = 102
Subtract 6 from both sides.
3x = 96
Divide 3 on both sides:
x = 32

So the first number is 32, which means the other 2 numbers are 34, and 36. 
To check our answer, let's put the numbers in the equation.

32 + 32 + 2 + 32 + 4 = 102
Yep! That's correct.

The answer is 32, 34, and 36.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
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The midpoint of AB is (3,2). If point is is located at(8,4) what are the coordinates of point B
Dmitry [639]

Step-by-step explanation:

8-3 = 5,

3-5 = -2 = the x coordinate of B

-2-4 =-6,

-2-6 =-8 = the y coordinate of B

(-2,-8) is the point B

A is 5 to the right of the midpoint, so B is 5 to the left of the midpoint

A is 6 up from the midpoint so B is 6 down from the midpoint

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2 years ago
Me and my friends have been arguing over this for a long time since we can't do math-
Arada [10]

Answer:

ur right

it's -1013

bc you need to do multiplication first so the equation turns out to be

10 - 1000 - 23

so then that turns to -1013 if you calculate left to right

What did ur friend get???

5 0
3 years ago
A man wins in a gambling game if he gets two heads in five flips of a biased coin. the probability of getting a head with the co
Semenov [28]

The probability the man will win will be 13.23%. And the probability of winning if he wins by getting at least four heads in five flips will be 36.01%.

<h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials.

Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

P(X = x) = ⁿCₓ pˣ (1 - p)⁽ⁿ⁻ˣ⁾

A man wins in a gambling game if he gets two heads in five flips of a biased coin. the probability of getting a head with the coin is 0.7.

Then we have

p = 0.7

n = 5

Then the probability the man will win will be

P(X = 2) = ⁵C₂ (0.7)² (1 - 0.7)⁽⁵⁻²⁾

P(X = 2) = 10 x 0.49 x 0.027

P(X = 2) = 0.1323

P(X = 2) = 13.23%

Then the probability of winning if he wins by getting at least four heads in five flips will be

P(X = 4) = ⁵C₄ (0.7)⁴ (1 - 0.7)⁽⁵⁻⁴⁾

P(X = 4) = 5 x 0.2401 x 0.3

P(X = 4) = 0.3601

P(X = 4) = 36.01%

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

4 0
2 years ago
Someone please help :) will mark brainliest :)
Nitella [24]

Answer:

a+b

Step-by-step explanation:

7 0
3 years ago
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ritas total bill at a restaurant was 25.00 including tax. if she left a tip of 20% of the total bill, what was the amount of the
Nadusha1986 [10]

Answer:

She left a $2 tip

Step-by-step explanation:

0.2*25 = 5

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