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uranmaximum [27]
3 years ago
13

What three consecutive even numbers add up to 102?

Mathematics
2 answers:
Nookie1986 [14]3 years ago
8 0
The answer to this question is 32,34,36
Daniel [21]3 years ago
6 0
So first you have to understand what consecutive numbers are.
Consecutive numbers are numbers like 4, 6, 8, 10, or 16, 18, 20. 

So let's set up an equation, using x as the first consecutive number. 
x + x + 2 + x + 4 = 102
Then simplify:
3x + 6 = 102
Subtract 6 from both sides.
3x = 96
Divide 3 on both sides:
x = 32

So the first number is 32, which means the other 2 numbers are 34, and 36. 
To check our answer, let's put the numbers in the equation.

32 + 32 + 2 + 32 + 4 = 102
Yep! That's correct.

The answer is 32, 34, and 36.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
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A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
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Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

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