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uranmaximum [27]
3 years ago
13

What three consecutive even numbers add up to 102?

Mathematics
2 answers:
Nookie1986 [14]3 years ago
8 0
The answer to this question is 32,34,36
Daniel [21]3 years ago
6 0
So first you have to understand what consecutive numbers are.
Consecutive numbers are numbers like 4, 6, 8, 10, or 16, 18, 20. 

So let's set up an equation, using x as the first consecutive number. 
x + x + 2 + x + 4 = 102
Then simplify:
3x + 6 = 102
Subtract 6 from both sides.
3x = 96
Divide 3 on both sides:
x = 32

So the first number is 32, which means the other 2 numbers are 34, and 36. 
To check our answer, let's put the numbers in the equation.

32 + 32 + 2 + 32 + 4 = 102
Yep! That's correct.

The answer is 32, 34, and 36.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
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Solve 2 log(x) + log(5) = log (80) using the one-to-one property.
vodomira [7]

x=4

Step-by-step explanation:

2log(x)+log(5)=log(80)

log(x^2)+log(5)=log(80)

log(5x^2)=log(80)

5x^2 =80

x^2 =80/5

x^2=16 , taking square root both sides

x=√16

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5 0
2 years ago
With double-digit annual percentage increases in the cost of health insurance, more and more workers are likely to lack health i
Dahasolnce [82]

Answer:

1.  χ² = <u>  15.3902 </u>

2. The p value is :_____.a. less than .005

3.  Conclusion

a. health insurance coverage is not independent of the size of the company

4. The percentages of employees

Small %=   33/50= 0.66

Medium %= 68/75 = 0.91

Large %= 88/100= 0.88

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0: the employee health insurance coverage is independent of the size of the company

against the claim

Ha: the employee health insurance coverage is not independent of the size of the company

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (O - E)²/ E where O is the observed and E is the expected frequency

which has an approximate chi square distribution with ( 3-1) (2-1)=  2 d.f

4) Computations:

Under H0 , the observed frequencies are :

Observed       Expected E        (O-E)         (O-E)²             (O-E)²/E

33                   42                      -9               81                    1.928  

68                  63                         5              25                  0.3968

88                  84                         4               16                  0.1904

17                    8                           9              81                  10.125

7                     12                          -5             21                    1.75

<u>12                    16                         -4              16                     1              </u>

<u>                                                                                           15.3902    </u>

Expected Values are calculated using the formula :

Row Total * Column Total / sample size

E1= (33+17) (33+ 68+88)/ 50+75+100= 42

E4= (33+17) (17+ 7+ 12)/ 50+75+100=8

E2= (68+7) (33+ 68+88)/ 50+75+100= 63

E5= (68+7)  (17+ 7+ 12)/ 50+75+100= 12

E3= (88+12) (33+ 68+88)/ 50+75+100= 84

E6= (88+12)  (17+ 7+ 12)/ 50+75+100= 16

5) The critical region is χ² ≥ χ² (0.05)2 = 5.99

6) Conclusion:

The calculated χ² = <u>  15.3902    </u>falls in the critical region χ² ≥  5.99  so we reject the null hypothesis that the employee health insurance coverage is NOT independent of the size of the company.

2. The p value is :_____.

a. less than .005

The p-value is .000385.

3.  Conclusion

a. health insurance coverage is not independent of the size of the company

4. The percentages of employees

Small %=   33/50= 0.66

Medium %= 68/75 = 0.91

Large %= 88/100= 0.88

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Answer:

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Answer:

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Step-by-step explanation:

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