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Thepotemich [5.8K]
3 years ago
15

A scale model of a city has a scale of 1 cm : 2.5 km. Two buildings in the model are 1.7 cm apart. To the nearest tenth of a kil

ometer, what is the actual distance between the buildings in the city
Mathematics
1 answer:
spin [16.1K]3 years ago
4 0
This is the concept of linear proportionality, we are required to calculate the actual length between two buildings which have a distance of 1.7 cm when drawn to scale of 1 cm: 2.5 km. This can be calculated as follows;
actual distance= (distance on the map)*(scale factor)
actual distance=1.7*2.5=4.25 km

The answer is 4.25 km
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Step-by-step explanation:

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Answer:


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<em><u>Given</u></em><u>:</u>       A line m is perpendicular to the angle bisector of ∠A. We call this  

                 intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

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<u><em>To Prove</em></u>:   <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>

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                  AD=AD                ...(2) (∵common side)

                  ∠ADM=∠ADN     ...(3) (∵Given)

                  <u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>

                                                         ( ∵ ASA  congruence rule)

                  ⇒<u><em> AM=AN</em></u>

                  Now, In Δ AMN

                 AM=AN (∵ Proved)

                  Hence, ΔAMN is an isosceles  triangle.


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