Make a ten or hundred to add mentally 198+132

1 answer:

6 0

2000. Because if you add the 2 it will make 1200, 2+8 is 10 so you carry the 1, and 3+9 is 12 then you add the 1 you got from 10 and you have 13. then you add 1+1 and get 2 and add the 1 you got from 13 so there you have it.

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Alenkasestr [34]

3•y+2
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3 0

3 years ago

Solve 2 cube root 8x+9=5

Alborosie

2 times the cube root of 8x+9=5
divide both sides by 2
cube root of 8x+9=2.5
cube everybody (put to 3rd power)
8x+9=2.5^3
8x+9=15.625
minus 9 both sides
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3 years ago

Sangeet got 96% of his answers right in a test of 50 marks. What was his score out of 50?

Ulleksa [173]

Answer:

48 out of 50 correct answers

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3 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0

3 years ago

a contractor needs to purchase 500 bricks. the dimensions of each brick are 5.1 cm by 10.2 by 20.3 cm, and the density of each b

AveGali [126]

No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.

5 0

4 years ago