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Brut [27]
3 years ago
11

The homeowner's association is sponsoring a spaghetti supper. Tickets to the event cost $10.50 per person. Sixty-two people have

already purchased tickets. The total number of tickets available is 245. If y = 10.50x represents the amount of money that can be received from the number of tickets that REMAIN to be sold, what values are appropriate for the domain of the function?
A. x > 62

B. 1 < x ≤183

C. 0 ≤ x ≤183

D. 62 ≤ x ≤245
Mathematics
1 answer:
den301095 [7]3 years ago
6 0

Answer:

i think c

Step-by-step explanation:

not sure

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kati45 [8]

Answer:

I really do not know.

Step-by-step explanation:

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3 years ago
Read 2 more answers
The number of yards of fabric needed for Robs costume is (7/8+1/2+1 3/4)÷2. How does the amount of fabric needed for Robs costum
exis [7]

The amount of fabric needed for Jimmy's costume is not stated, we can only determine the amount needed for Rob's costume, which makes it impossible to compare the amounts needed for both of their costumes. If this omission was an error, then you can find the difference between these amounts if the amount needed for Jimmy's costume is stated explicitly.

Step-by-step explanation:

The number of yards of fabric needed for Robs costume is (7/8+1/2+1 3/4)÷2

Assuming 1 3/4 is a mixed fraction.

= (7/8 + 1/2 + 7/4) ÷ 2

= (7 + 4 + 2) ÷ (8 × 2)

= 13/16 yards

Suppose 2 yards of fabric is needed for Jimmy's costume, then comparing with Rob's yards, we see that Jimmy's costume requires (2 - 13/16 = 19/16) more yards than Rob's costume.

8 0
4 years ago
Simplify. 3/5 +(− 1/4 ) 7/10 Enter your answer, in simplest form, in the boxes.
vitfil [10]

3/5+(-7/40)

=3/5-7/40

=24/40-7/40

=17/40

8 0
4 years ago
Read 2 more answers
What times what gets you to 41
Viktor [21]

Answer:

1 x 41 = 41............….…...

7 0
3 years ago
Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly
kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0
3 years ago
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