Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
<h3>
Inscribing a square</h3>
The steps involved in inscribing a square in a circle include;
- A diameter of the circle is drawn.
- A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
- The resulting four points on the circle are the vertices of the inscribed square.
Alicia deductions were;
Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle
Benjamin's deductions;
The diameters must be perpendicular to each other. Then connect the points, in order, around the circle
Caleb's deduction;
No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.
It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.
Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
Learn more about an inscribed square here:
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Answer:
It means that the roots of the quadratic equation are real and distinct
Step-by-step explanation:
Here, given the discriminant of the quadratic equation, we want to find out the nature of the solutions.
Mathematically, we can use to determine the nature of the discriminant.
By it’s formula;
D = b^2 - 4ac
We can see that the given discriminant 40 is a positive value. What this means is that the quadratic equation has roots which are real and are distinct
Simple just do normal simple algebra:)
Answer:
y = 
x - 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) =( 8, - 3) and (x₂, y₂ ) = (0, - 5)
m = 
= 
=
Note the line crosses the y- axis at (0, - 5 ) ⇒ c = - 5
y = x - 5 ← equation of line
Answer:
Option (d).
Step-by-step explanation:
Note: The base of log is missing in h(x).
Consider the given functions are
The function m(x) can be written as
...(1)
The translation is defined as
.... (2)
Where, a is horizontal shift and b is vertical shift.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
On comparing (1) and (2), we get
Therefore, we have to translate each point of the graph of h(x) 3 units left to get the graph of m(x).
Hence, option (d) is correct.
