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maks197457 [2]
2 years ago
7

Solve the problem below

Mathematics
2 answers:
frez [133]2 years ago
7 0
<h3>Answer:  207 degrees</h3>

===========================================================

Explanation:

Refer to the diagram below.

There's a lot of info given to us that we don't need (and won't use).

The only key piece of info we'll really use is the fact that angle XZY is 27 degrees.

Draw in segments RU and RT to form quadrilateral TRUZ

Focusing solely on this quadrilateral, we see that the angles T and U are 90 degrees each (since the tangents are perpendicular to the radii at the point of tangency). Furthermore, we see that angle Z is 27 while angle R is x

For any quadrilateral, the four angles always add to 360 degrees

T+R+U+Z = 360

90+x+90+27 = 360

x+207 = 360

x = 360-207

x = 153

That means angle R of quadrilateral TRUZ is 153 degrees.

Furthermore, it means angle TRU is 153 degrees.

By extension, it indicates that minor arc TU is 153 degrees.

That makes arc TSU = 360 - (minor arc TU) = 360 - 153 = 207 degrees

Neporo4naja [7]2 years ago
6 0

By Joining TR and UR we got 2 right angles and a Quadrilateral

now

In a Quadrilateral sum of angles=360°

\\ \large\sf\longmapsto x+90+90+27=360

\\ \large\sf\longmapsto x+180+27=360

\\ \large\sf\longmapsto x+207=360

\\ \large\sf\longmapsto x=360-207

\\ \large\sf\longmapsto x=153°

  • <TSU =360-153=207°
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Step-by-step explanation:

A) p ( proportion of population that spends more than $100 per week) = 0.17

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the sample proportion of p = 0.17

standard error of p = \sqrt{\frac{p(1-p)}{n} } = 0.013281

the sampling distribution of p can be calculated/approximated with

normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) probability that the sample proportion will be +-0.02 of the population proportion

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z value corresponding to P

Z = \frac{P - p}{standard deviation}

at P = 0.15

Z =  (0.15 - 0.17) / 0.013281 = = -1.51

at P = 0.19

z = ( 0.19 - 0.17) / 0.013281 = 1.51

therefore the required probability will be

p( -1.5 ≤ z ≤ 1.5 ) = p(z ≤ 1.51 ) - p(z ≤ -1.51 )

                           = 0.9345 - 0.0655 = 0.869

C) for a sample (n ) = 1600

standard deviation/ error = 0.009391 (applying the equation for calculating standard error as seen in part A above)

therefore the required probability after applying

z = \frac{P-p}{standard deviation} at p = 0.15 and p = 0.19

p ( -2.13 ≤ z ≤ 2.13 ) = p( z ≤ 2.13 ) - p( z ≤ -2.13 )

                               = 0.9834 - 0.0166 = 0.9668

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Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.32)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

Part b

P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]

P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211  

P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

Part c

P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264

P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218

P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123

P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

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