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Oduvanchick [21]

4 years ago

9

Coach Fraser will select a captain and a co-captain from the students in her physical education class. If there are 22 students

from which to
select, how many different outcomes are possible?
a. 484
b. 462
c. 44
d. 22

2 answers:

Pachacha [2.7K]4 years ago

7 0

Answer:462

Step-by-step explanation:

solong [7]4 years ago

5 0

Answer:

The answer is B

Step-by-step explanation:

22 runs into 464 with this many out comes

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lana [24]

Answer:

$3.60.

Step-by-step explanation:

4.5 = x + 20% of x

4.5 = x + 0.2x

1.2x = 4.5

x = 3.75

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2 years ago

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kifflom [539]

Answer:

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Step-by-step explanation:

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3 years ago

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scoray [572]

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3 0

3 years ago

- 5 .5 ( d - 2 ) = - 12. 1

OverLord2011 [107]

Answer:

D = 4.2

Step-by-step explanation:

-5.5 ( d - 2 ) = - 12.1

-5.5d + 11 = - 12.1

11 + 12.1 = 5.5d

23.1 = 5.5d

d = 23.1 ÷ 5.5

d = 4.2

5 0

3 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0

3 years ago