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3 years ago

FIRST TO ANSWER GETS BRAINLIEST

Mathematics

2 answers:

qaws [65]3 years ago

7 0

c is the correct answer to your problem

olga2289 [7]3 years ago

5 0

Answer:

The answer is ΔJMK ≈ ΔMLK ≈ ΔJLM ⇒ answer (A)

Step-by-step explanation:

* Lets start with the equal angles i the three triangles

- In ΔJMK

∵ m∠JKM = 90°

∴ m∠KJM + m∠KMJ = 90 ⇒ (1)

- IN ΔMLK

∵ m∠MKL = 90°

∴ m∠KML + m∠KLM = 90° ⇒ (2)

∵ m∠KMJ + m∠KML = 90° ⇒ (3)

- From (1) , (2) , (3)

∴ m∠KJM = m∠KML

∴ m∠KMJ = m∠KLM

* Now lets check the condition of similarity in the 3 triangles

- At first ΔJMK and ΔMLK

- In triangles JMK , MLK

∵ m∠KJM = m∠KML

∵ m∠KMJ = m∠KLM

∵ m∠JKM = m∠MKL

∴ ΔJMK ≈ ΔMLK ⇒ (4)

- At second ΔJMK and ΔJLM

∵ m∠KJM = m∠MJL

∵ m∠KMJ = m∠MLJ

∵ m∠JKM = m∠JML

∴ ΔJMK ≈ ΔJLM ⇒ (5)

* If two triangles are similar to one triangle, then they are

similar to each other

- From (4) and(5)

∴ ΔJMK ≈ ΔMLK ≈ ΔJLM

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2 years ago

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<h3>Answer: cos(76)</h3>

=========================================================

Explanation:

The original expression is of the pattern cos cos + sin sin. This pattern matches the second identity in the hint. Specifically, we'll say the following:

cos(A - B) = cos(A)cos(B) + sin(A)sin(B)

cos(A)cos(B) + sin(A)sin(B) = cos(A - B)

cos(94)cos(18) + sin(94)sin(18) = cos(94 - 18)

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----------

We can verify this by use of a calculator. Make sure your calculator is in degree mode.

cos(94)cos(18) + sin(94)sin(18) = 0.24192
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Both expressions give the same decimal approximation, so this helps confirm the two expressions are equal. You could also use the idea that if x = y, then x-y = 0. Through this method, you'll subtract the left and right hand sides and you should get (very close to) zero.

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