Question

FIRST TO ANSWER GETS BRAINLIEST

Answer 1

c is the correct answer to your problem

Answer 2

Answer:

The answer is ΔJMK ≈ ΔMLK ≈ ΔJLM ⇒ answer (A)

Step-by-step explanation:

* Lets start with the equal angles i the three triangles

- In ΔJMK

∵ m∠JKM = 90°

∴ m∠KJM + m∠KMJ = 90 ⇒ (1)

- IN ΔMLK

∵ m∠MKL = 90°

∴ m∠KML + m∠KLM = 90° ⇒ (2)

∵ m∠KMJ + m∠KML = 90° ⇒ (3)

- From (1) , (2) , (3)

∴ m∠KJM = m∠KML

∴ m∠KMJ = m∠KLM

* Now lets check the condition of similarity in the 3 triangles

- At first ΔJMK and ΔMLK

- In triangles JMK , MLK

∵ m∠KJM = m∠KML

∵ m∠KMJ = m∠KLM

∵ m∠JKM = m∠MKL

∴ ΔJMK ≈ ΔMLK ⇒ (4)

- At second ΔJMK and ΔJLM

∵ m∠KJM = m∠MJL

∵ m∠KMJ = m∠MLJ

∵ m∠JKM = m∠JML

∴ ΔJMK ≈ ΔJLM ⇒ (5)

* If two triangles are similar to one triangle, then they are

 similar to each other

- From (4) and(5)

∴ ΔJMK ≈ ΔMLK ≈ ΔJLM