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3 years ago

FIRST TO ANSWER GETS BRAINLIEST

Mathematics

2 answers:

qaws [65]3 years ago

7 0

c is the correct answer to your problem

olga2289 [7]3 years ago

5 0

Answer:

The answer is ΔJMK ≈ ΔMLK ≈ ΔJLM ⇒ answer (A)

Step-by-step explanation:

* Lets start with the equal angles i the three triangles

- In ΔJMK

∵ m∠JKM = 90°

∴ m∠KJM + m∠KMJ = 90 ⇒ (1)

- IN ΔMLK

∵ m∠MKL = 90°

∴ m∠KML + m∠KLM = 90° ⇒ (2)

∵ m∠KMJ + m∠KML = 90° ⇒ (3)

- From (1) , (2) , (3)

∴ m∠KJM = m∠KML

∴ m∠KMJ = m∠KLM

* Now lets check the condition of similarity in the 3 triangles

- At first ΔJMK and ΔMLK

- In triangles JMK , MLK

∵ m∠KJM = m∠KML

∵ m∠KMJ = m∠KLM

∵ m∠JKM = m∠MKL

∴ ΔJMK ≈ ΔMLK ⇒ (4)

- At second ΔJMK and ΔJLM

∵ m∠KJM = m∠MJL

∵ m∠KMJ = m∠MLJ

∵ m∠JKM = m∠JML

∴ ΔJMK ≈ ΔJLM ⇒ (5)

* If two triangles are similar to one triangle, then they are

similar to each other

- From (4) and(5)

∴ ΔJMK ≈ ΔMLK ≈ ΔJLM

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Find all natural numbers n such that 1+3+5+7+...+(2n-1) sum is divisible by 4

Ierofanga [76]

n ∈ natural even numbers

Step-by-step explanation:

1 + 3 + 5 + 7 + … + (2n-1)

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b = 2
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Sₙ = n/2(a + Uₙ)

Sₙ = n/2(1 + 2n - 1)

Sₙ = n/2(2n)

Sₙ = n²

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Find x<br> 25<br> 7<br> х<br> I need help

Murljashka [212]

Answer:

24 = x

Step-by-step explanation:

You use Pythagorean theorem. Since the normal equation is $a^{2} + b^{2} =c^{2}$ , you already have the $c^{2}$ and another side which can be $a^{2}$ or $b^{2}$ .

Because you have the hypotenuse and a side , your equation looks like this now: $7^{2} +b^{2} = 25^{2}$

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2 years ago

Calculate f(x) for the given domain values.

Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

1. The given function is

$f(x) = - 3x$

The domain values are: x=0, 2, -1, 4, -2

When x=0

$f(0) = - 3 \times 0 = 0$

When x=2,

$f(x) = - 3 \times 2 = - 6$

When x=-1

$f(x) = - 3 \times - 1 = 3$

When x=4

$f(4) = - 3 \times 4 = - 12$

When x=-2

$f( - 2) = - 3 \times - 2 = 6$

2. The given function is

$f(x) = \frac{1}{3} x$

When x=3,

$f(3) = \frac{1}{3} \times 3 = 1$

Similarly,

$f( - 3) = \frac{1}{3} \times - 3 = - 1$

$f(300) = \frac{1}{3} \times 300 = 100$

$f( - 180) = \frac{1}{3} \times - 180 = - 60$

$f(99) = \frac{1}{3} \times 99 = 33$

8 0

3 years ago

Youth tickets(y) cost $2 for a ride, while adult tickets(x) cost $3. The amount of money earned is $54. If all the seats were fi

Paha777 [63]

There are no constants here. But we have x and y here.
We will create an equation which is:
2y+3x=54.
But we will also create a second equation which states the number of seats.
x+y=24.

Now we do the two-equation solving method.
2y+3x=54
-2(x+y=24)

2y+3x=54
-2x-2y=-48

x=6

To solve for y, plug in x into one of the original equations. Which one doesn't matter.

y+6=24
y=18

7 0

3 years ago