Answer:
0.0008032
Step-by-step explanation:
Hope this helps!
Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
It is C..........................Happy Birthday
15.5 I believe but don’t hold me to it!
If we had AB: BC: CD, we could easily have solved that problem. In order to combine these ratios, we need to have the same number for BC. We can create this number by finding LCM (Least Common Multiple) for 5 and 3, which is 15. Then, we can write ratios of AB:BC = 6:15 and BC:CD=15:20. Now, we can easily combine these ratios. AB:BC:CD = 6:15:20. Then, 6k+15k+20k = 82 and k=2 cm. And BC = 30 cm