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3 years ago

What is the emperor call formula for a compound that is 31.9% potassium 28.9% chloride and 39.2% oxygen

1 answer:

3 0

Lets take 100 g compound.
It will have
K - 31.9 g
Cl - 28.9 g
O - 39.2 g

M(K) = 39.1 g/mol
M(Cl) = 35.5 g/mol
M(O) = 16.0 g/mol

K - 31.9 g*1/mol/39.1 g ≈ 0.816 mol
Cl - 28.9 g*1 mol/35.5 g ≈ 0.814 mol
O - 39.2 g*1mol/16.0 g ≈ 2.45 mol

K : Cl : O = 0.816 : 0.814 : 2.45

K : Cl : O = 1 : 1 : 3

KClO3 - potassium chlorate (Berthelot's salt)

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kotegsom [21]

Answer: The final temperature of water is 32.3°C

Explanation:

When two solutions are mixed, the amount of heat released by solution 1 (liquid water) will be equal to the amount of heat absorbed by solution 2 (liquid water)

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$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

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where,

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$m_2$ = mass of solution 2 (liquid water) = 29.0 g

$T_{final}$ = final temperature = ?

$T_1$ = initial temperature of solution 1 = 25°C = [273 + 25] = 298 K

$T_2$ = initial temperature of solution 2 = 45°C = [273 + 45] = 318 K

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Putting values in equation 1, we get:

$50.0\times 4.18\times (T_{final}-298)=-[29.0\times 4.18\times (T_{final}-318)]\\\\T_{final}=305.3K$

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3 years ago

What is the molarity of a solution that contains 2 moles of solute in 4 liters of solution?

Nitella [24]

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3 years ago

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Oksanka [162]

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