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Paha777 [63]
2 years ago
7

Can someone convert 150 cm of copper (Cu) wire into mm of Cu wire?​

Chemistry
1 answer:
Vedmedyk [2.9K]2 years ago
6 0

1500 mm of copper wire are produced by converting 150 cm of copper wire.

The following is the centimeter to millimeter conversion factor: 1 cm is equivalent to 10 mm.

Consequently, 150 cm will equal 150 x 10 = 1500 mm.

  • The multi-step process of unit conversion involves multiplying or dividing by a numerical factor.
  • Unit conversion is the process of converting the measurement of a given amount between various units, often by multiplicative conversion factors that alter the value of the measured quantity without altering its effects.
  • Unit conversion is a multi-step procedure that involves adding, subtracting, multiplying, or dividing by a conversion factor.
  • The process may also require the selection of the correct number of significant digits, and rounding.

To learn more about unit conversion visit:

brainly.com/question/11543684

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The compound cisplatin, pt(nh3)2cl2 , has been studied extensively as an antitumor agent.
Nataliya [291]

a. Elemental percent composition is the mass percent of each element in the compound.

The formula for mass elemental percent composition = \frac{mass of element}{mass of compound}   (1)

The molecular formula of cisplatin is Pt(NH_3)_2Cl_2.

The atomic weight of the elements in cisplatin is:

Platinum, Pt = 195.084 u

Nitrogen, N = 14.0067 u

Hydrogen, H = 1 u

Chlorine, Cl = 35.453 u

The molar mass of Pt(NH_3)_2Cl_2 = 195.084+ (2\times 14.0067)+(6\times 1)+(2\times 35.453) = 300.00 g/mol

The mass of each element calculated using formula (1):

- Platinum, Pt %

\frac{195.084}{300.00} \times 100 = 65.23%.

- Nitrogen, N%

\frac{2\times 14.0067}{300.00} \times 100 = 9.34%

- Hydrogen, H%

\frac{6\times 1}{300.00} \times 100 = 2.0%

- Chlorine, Cl%

\frac{2\times 35.453}{300.00} \times 100 = 23.63%

b. The given reaction of cisplatin is:

K_2PtCl_4(aq)+2NH_3(aq)\rightarrow Pt(NH_3)_2Cl_2(s)+2KCl(aq)

According to the balanced reaction, 1 mole of K_2PtCl_4 gives 1 mole of Pt(NH_3)_2Cl_2.

Now, calculating the number of moles of K_2PtCl_4 in 100.0 g.

Number of moles = \frac{given mass}{Molar mass}

Molar mass of K_2PtCl_4 = 2\times 39.0983+195.084+4\times 35.453 = 415.093 g/mol

Number of moles of K_2PtCl_4 = \frac{100 g}{415.093 g/mol} = 0.241 mole.

Since, 1 mole of K_2PtCl_4 gives 1 mole of Pt(NH_3)_2Cl_2. Therefore, mass of cisplatin is:

0.241 mole\times 300 g/mol = 72.3 g

For mass of KCl:

Molar mass of KCl = 39.0983 + 35.453 = 74.55 g/mol

Since, 1 mole of K_2PtCl_4 gives 2 mole of KCl. Therefore, mass of KCl is:

0.241 mole\times 74.55 g/mol\times 2 = 35.93 g


5 0
3 years ago
if you could place a piece of solid silver into a container of liquid silver, would it float or sink? Explain your answer
olga55 [171]
Liquid silver is less dense than solid silver, so the solid silver would sink.
5 0
3 years ago
Read 2 more answers
Container A (with volume 1.23 L) contains a gas under 3.24 atm of pressure. Container B (with volume
kolbaska11 [484]

Now that a lot of pressure

8 0
3 years ago
Using the balanced equation for the combustion of ethane: 2C2H6 + 7O2 → 4CO2 + 6H2O, how many moles of O2 needed to produce 12 m
pickupchik [31]

Answer:

14 moles of oxygen needed to produce 12 moles of H2O.

Explanation:

We are given that balance eqaution

2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O

We have to find number of moles of O2 needed  to produce 12 moles of H2O.

From given equation

We can see that

6 moles of   H2O produced by Oxygen =7 moles

1 mole of   H2O produced by Oxygen=\frac{7}{6}moles

12 moles of H2O produced by Oxygen=\frac{7}{6}\times 12moles

12 moles of H2O produced by Oxygen=7\times 2moles

12 moles of H2O produced by Oxygen=14 moles

Hence, 14 moles of oxygen needed to produce 12 moles of H2O.

3 0
3 years ago
According to the ideal gas law, increasing the volume of a closed reaction container decreases the thermal energy because the
hichkok12 [17]

Answer:

b is ur answer the temputer does increase

Explanation:

8 0
3 years ago
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