9514 1404 393
Answer:
5/9 m/min
Step-by-step explanation:
The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:
2/5 × 2 m = 4/5 m
Then the surface area of the water is ...
A = LW = (18 m)(4/5 m) = 14.4 m²
The rate of change of height multiplied by the area gives the rate of change of volume:
8 m³/min = (14.4 m²)(h')
h' = (8 m³/min)/(14.4 m²) = 5/9 m/min
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
Answer:
lo que opinaria sería modo serio pero en realidad no pero bueno lo que creo que sería bien sería pieseses pero eso tiene cosa que ver con la metoforsosis o como se llame
Answer:
y = 5
Step-by-step explanation:
Since this is an isosceles triangle, Angle B and Angle C are equivalent. We can use this to find x
3x = 75
x = 25
Angles in a triangle add up to 180, so knowing the measure of Angle B and Angle C, we can find the measure of Angle A
Angle A = 180-(75+75)
Angle A = 180-150
Angle A = 30
We know Angle A = 4y+10
4y + 10 = 30
4y = 20
y = 5
