Answer:
5
Step-by-step explanation:
Answer:
No Real Solutions.
Step-by-step explanation:
√(x-5)=8√(x-2)
Square on both sides,
(√(x-5))^2=(8√(x-2))^2
or,(x-5)=64(x-2)
or,x-5=64x-128
or,-5+128=64x-x
or,123/63=x
Therefore, x=41/21
If you plug x=41/21 in √(x-5)=8√(x-2) you do not get equals, so the problem has no real solutions.
4a5+28+6b7-30
4a5+6b7-2<—- this is a to the power of 5 , b to the power of 7
(Is that 5a or a to the power of 5 )
20a+28+42b-30
20a+42b-2<—— this is 5a , 7b
Answer:
The slopes are
Therefore, the equations are equations of <u> Perpendicular Lines .</u>
Step-by-step explanation:
Given:
......................Equation ( 1 )
..............Equation ( 2 )
To Find:
Slope of equation 1 = ?
Slope of equation 2 = ?
Solution:
On comparing with slope point form
Where,
m = Slope
c = y-intercept
We get
Step 1.
Slope of equation 1 = m1 = 
Step 2.
Slope of equation 1 = m2 = 
Step 3.
Product of Slopes = m1 × m2 = 
Product of Slopes = m1 × m2 = -1
Which is the condition for Perpendicular Lines
The slopes are
Therefore, the equations are equations of <u> Perpendicular Lines . </u>
Whenever you are given a scale factor, that factor will apply to each dimension and because area is a two dimensional measurement, you multiply the area by 5 twice (so x5 x5). This means the new area would be 154x5^2. The new area of the photograph is 3850 square inches.
