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2 answers:
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Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
<u>364 cm²</u>
Step-by-step explanation:
Area of the figure :
- Area (triangle) + Area (rectangle 1) + Area (rectangle 2) + Area (rectangle 3)
- 1/2 x 20 x 14 + 12 x 9 + 7 x 3 + 19 x 5
- 140 + 108 + 21 + 95
- 248 + 21 + 95
- 269 + 95
- <u>364 cm²</u>
