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Minchanka [31]
3 years ago
15

Find two consecutive positive even numbers

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0

Answer:

-4,2

Step-by-step explanation:

let \: two \: consecutive \: even \: numbers \: be \: x \: and \: x + 2 \\ so \: by \: the \: question \\  {x}^{2}  +  {(x + 2)}^{2}  = 20 \\ or \:  {x}^{2}  +  {x}^{2}  + 4x + 4 = 20 \\ or \: 2 {x}^{2}  + 4x = 20 - 4 \\ or \: 2( {x}^{2}   + 2x) = 16 \\ or {x}^{2}  + 2x = 8 \\ or \:  {x}^{2}  + 2x - 8 = 0 \\ or \:  {x}^{2}   + (4 - 2)x - 8 = 0 \\ or \:  {x}^{2}   + 4x  -  2x - 8 = 0 \\ or \: x(x + 4) - 2(x + 4) = 0 \\ or \: (x + 4)(x - 2) = 0 \\ either \: x + 4 = 0 \\ or \: x =  - 4 \\ or \: x - 2 = 0 \\ orx = 2

therefore, x= -4 and 2

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If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH
olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

\angle EFG=\angle EFH+\angle HFG

18x+11=(5x+1)+(62)

18x+11=5x+63

Isolate variable terms.

18x-5x=63-11

13x=52

Divide both sides by 13.

x=\dfrac{52}{13}

x=4

The value of x is 4.

\angle EFH=(5x+1)^\circ

\angle EFH=(5(4)+1)^\circ

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\angle EFH=21^\circ

Therefore, the measure of ∠EFH is 21°.

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3 years ago
What is -38/-5 as a decimal?
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5 0
3 years ago
Match the circle equations in general form with their corresponding equations in standard form. x2 y2 − 4x 12y − 20 = 0 (x − 6)2
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The equation given is matched with the respective vertex forms.

<h3>What is the standard Equation for a circle ?</h3>

The standard equation for a circle is given by

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The equation given in the question are

x² + y²  − 4x + 12y − 20 = 0

(x − 6)²  + (y − 4)²  = 56

x²  + y²  + 6x − 8y − 10 = 0

(x − 2)²  + (y + 6)²  = 60

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(x+3)²  + (y-4)²  = 35

2x²  + 2y²  − 24x − 16y − 8 = 0

(x-1)²  + (y+2)²   = 11

The first equation is

x² + y²  − 4x + 12y − 20 = 0

It can be written ad

x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0

(x-2)² +(y+6)²= 60

The second equation is

x²  + y²  + 6x − 8y − 10 = 0

x² +6x +9-9 +y²  -8y +16-16 -10 = 0

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(x − 6)²  + (y − 4)²  = 56

To know more about standard equation of Circle

brainly.com/question/13658927

#SPJ1

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