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3 years ago

Find two consecutive positive even numbers

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

6 0

Answer:

-4,2

Step-by-step explanation:

$let \: two \: consecutive \: even \: numbers \: be \: x \: and \: x + 2 \\ so \: by \: the \: question \\ {x}^{2} + {(x + 2)}^{2} = 20 \\ or \: {x}^{2} + {x}^{2} + 4x + 4 = 20 \\ or \: 2 {x}^{2} + 4x = 20 - 4 \\ or \: 2( {x}^{2} + 2x) = 16 \\ or {x}^{2} + 2x = 8 \\ or \: {x}^{2} + 2x - 8 = 0 \\ or \: {x}^{2} + (4 - 2)x - 8 = 0 \\ or \: {x}^{2} + 4x - 2x - 8 = 0 \\ or \: x(x + 4) - 2(x + 4) = 0 \\ or \: (x + 4)(x - 2) = 0 \\ either \: x + 4 = 0 \\ or \: x = - 4 \\ or \: x - 2 = 0 \\ orx = 2$

therefore, x= -4 and 2

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The solution to the problem is as follows:

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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3 years ago

Z varies jointly as x and y. z=60 when x=5 and y=6. find z when x = 7 and y=3

Aneli [31]

Answer:

z = 42

Step-by-step explanation:

The question can be answered in 2 steps as follows:

Step 1: Calculation of the constant of the variation

The equation for the joint variation can be given as follows:

z = cxy ................... (1)

Where;

z = 60

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Substituting the values into equation (1) and solve c, we have:

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Using the information above, we can find our answer:

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